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galina1969 [7]
3 years ago
13

Which statement accurately describes the outer planets?

Physics
2 answers:
tiny-mole [99]3 years ago
6 0
The outer planets have a high gravity due to their large size
True [87]3 years ago
5 0

Answer:

Its D on Edge 2020 just took the quiz

Explanation:

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The speed of light in vacuum is exactly 299,792,458 m/s. A beam of light has a wavelength of 651 nm in vacuum. This light propag
sukhopar [10]

Answer:

v=2.58\times10^8m/s

Explanation:

The index of refraction is equal to the speed of light c in vacuum divided by its speed v in a substance, or n=\frac{c}{v}. For our case we want to use v=\frac{c}{n}, which for our values is equal to:

v=\frac{c}{n}=\frac{299792458m/s}{1.16}=258441774.138m/s

Which we will express with 3 significant figures (since a product or quotient must contain the same number of significant figures as the measurement with the  <em>least</em> number of significant figures):

v=2.58\times10^8m/s

4 0
3 years ago
A 70- kg bicycle rides his 9.8- kg bicycle with a speed of 16 m/ s. What is the magnitude of the braking force of the bicycle co
Rus_ich [418]

Answer:

F = -319.2 N

Explanation:

Given that,

The mass of a bicyclist, m = 70 kg

Mass of the bicycle = 9.8 kg

The speed of a bicycle, v = 16 m/s

We need to find the magnitude of the braking force of the bicycle come to rest in 4.0 m.

The braking force is given by :

F=ma\\\\=\dfrac{m(v-u)}{t}\\\\=\dfrac{(70+9.8)(0-16)}{4}\\\\=-319.2\ N

So, the required force is 319.2 N.

3 0
2 years ago
Why is the sign of the emf of the second peak opposite to the sign of the first peak?
eimsori [14]
Because AC emf is a sine wave
7 0
2 years ago
What condition is necessary for an object to make a good reference point?
777dan777 [17]
The object is fixed relative to the motion you are trying to describe.
8 0
3 years ago
You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has—— energy. Calculate
Slav-nsk [51]

Answer:

945 j

Explanation:

You have just given the ball kinetic energy, which is given by the following equation:

KE= 1⁄2 m v2 = 1⁄2 (2.1 kg)(30 m/s)2 = 945 Joules

3 0
3 years ago
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