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3 years ago

Which statement accurately describes the outer planets?

Physics

2 answers:

tiny-mole [99]3 years ago

6 0

The outer planets have a high gravity due to their large size

True [87]3 years ago

5 0

Answer:

Its D on Edge 2020 just took the quiz

Explanation:

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Chang sees the following formula on a website about Newton’s second law. a = Sigma F over m.

Tems11 [23]

Answer:A) he needs to find the net force acting on an object in a direction.

Explanation:

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3 years ago

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Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink? Explain your answer

stealth61 [152]

Answer:

Sink

Explanation:

Water has a density of 1 g/cm³. Since the density of the rock is greater than the density of water, the rock will sink.

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3 years ago

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A 1.80-kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. The period for s

Evgen [1.6K]

Answer:

(a) I (Moment of inertia)=0.0987 $kgm^{2}$

(b) W(Angular Speed)=2.66 $\frac{rad}{s}$

Explanation:

Given data

m (Monkey mass)= 1.80 kg

d=2.50 m

T (Time Period)=0.940 s

Angle= 0.400 rad

(a) I (Moment of Inertia)=?

(b) W (Angular Speed)=?

For part (a) I (Moment of Inertia)=?

Time Period Formula is given as

$T=2(3.14)\sqrt{\frac{I}{mgd} }$

After Simplifying we get

$I=\frac{mgdT^{2} }{4*(3.14)^{2}}$

$I=\frac{1.8*9.8*0.25*(0.94)^{2} }{4(3.14)^{2} }$

$I=0.0987 kgm^{2}$

For Part (b) Angular Speed

From Kinetic Energy we get

$KE=\frac{1}{2}IW^{2}$

Pontential Energy

$PE=mgd(1-Cosa)$

KE=PE

$\frac{1}{2}IW^{2}=mgd(1-Cosa)$

$W^{2}=\frac{2mgd(1-Cosa)}{I}$

$W=\sqrt{\frac{2*1.8*9.8*0.25*(1-Cos(0.4)rad)}{0.0987} }$

$W=2.66\frac{rad}{s}$

5 0

3 years ago

a 3.5 kg mass has an initial velocity of 4.0 m/s. How much force is required to increase the velocity of the mass to 8.0 m/s in

Nadya [2.5K]

Answer:

<em>4.67 N of force are required</em>

Explanation:

The second Newton's law states the net force exerted on a body of mass m that has an acceleration a, is given by:

F=m.a

On the other hand, the kinematics equations relate the acceleration with the change of speed over time, expressed as:

$\displaystyle a=\frac{v_f-v_o}{t}$

We are given the initial speed of vo=4 m/s on a mass of m=3.5 Kg, the final speed of vf=8 m/s which took t=3 seconds.

The acceleration is:

$\displaystyle a=\frac{8-4}{3}=1.33$

$a=1.33\ m/s^2$

Thus, the force is:

$F=3.5\ Kg\cdot 1.33\ m/s^2$

$F=4.67\ N$

4.67 N of force are required

6 0

3 years ago

Answer this plsss<br> A mobile phone operates at 900 MHz. <br> What wavelength does it use?

Aleks [24]

Answer:

The wavelength = 0.3333 meters at 900 MHz, therefore, = /4 = 0.08333 meters.

7 0

3 years ago