Answer:
Step-by-step explanation:
2 consecutive integers represented as variables:
x, x + 1
Greater one: x + 1
Lesser one: x
Write as an equation
2(Greater) + 13 = 3(Lesser)
Substitute in known values
2(x + 1) + 13 = 3(x)
Multiply
2x + 2 + 13 = 3x
Subtract 2x from both sides of the equation
2 + 13 = x
Add 2 + 13 to simplify
x = 15
Lesser = x = 15
Greater = x + 1 = 15 + 1 = 16
Hope this helps :)
The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
Answer:
X= 15
Step-by-step explanation:
the above equation will be used to determine the value of x.
the above equation will be used to determine the value of x.
6x-12= 2x+20+18
6x-2x = 20+12+18
4x= 60.
X= 60/4
X= 15
x = 15
I think the answer is true.
Answer: [A]: "library card".
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Explanation: One would need a valid, government-issued photo ID card (i.e. that has not expires).
Although SOME library cards include one's picture, library cards do not constitute "valid ID's" because they are not "government-issued" and would, theoretically, be easy to be made fraudulently (e.g. not have security-issued seals and features).
Even "school ID's"; or "college ID cards"; even if "current" (e.g. currently enrolled" with a photo ID) would not be considered "official" and would only be considered "secondary ID".
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