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3 years ago

3. If we remember seeing something happen, we can trust that it happened just as we think it did. True or False

Chemistry

1 answer:

djverab [1.8K]3 years ago

3 0

$\huge{ \underbrace{ \overbrace{True}}}$

$\huge\mathfrak\purple{Hope \: it \: helps}$

Note : Because Many of My Dreams came true and I realized.

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12) Which statement is not a component of the particle kinetic molecular theory of matter? A) Atoms of different elements are id

agasfer [191]

Answer:

c i got it right on usatestprep

Explanation:

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2 years ago

12.5 mL of 6.0 M KCl is diluted to make a 1.5 L solution. The molarity of the dilution solution is ___ M. (Round atomic masses t

horsena [70]

The molarity of the dilution solution is 0.050 M

<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

Dilution formula :

$\tt M_1.V_1=M_2.V_2$

M₁=6 M

V₁=12.5 ml

V₂=1.5 L=1500 ml

$\tt 6\times 12.5=M_2\times 1500\\\\M_2=\dfrac{6\times 12.5}{1500}=0.05~M\\\\for~sig.fig\rightarrow 0.050~M$

4 0

3 years ago

6. Write the ICE chart for the reaction of 32.0 g of sulfur and 71.0 g of chlorine: S8 + 4 Cl24S2Cl2 After completing the chart

Marianna [84]

Answer:

ICE Table Figure

a. 67.37 g $S_2Cl_2$

b. 35.62 g $Cl_2$

c. 58.61 g $S_2Cl_2$

Explanation:

For the ICE table we have to keep in mind that we have 4 moles of $Cl_2$ and 1 mol of $S_8$ and the reactives are consumed, so for $Cl_2$ we will have -4X and for $S_8$ we will have -X. Follow the same logic we will have -4X for $S_2Cl_2$ .

a. Mass of the product

Molar mass of $S_8$ = 256.52 g/mol

Molar mass of $Cl_2$ =70.9 g/mol

Molar mass of $S_2Cl_2$ =135.03 g/mol

We have to find the limiting reagent in the reaction:

$S_8+4Cl_2->4S_2Cl_2$

$\frac{32}{256.52}=0.124molS_8$

$\frac{71}{70.9}=1 molCl_2$

Divide by the coefficients in the balanced reaction:

$\frac{0.124}{1}=0.124mol$

$\frac{1}{4}=0.25 mol$

The limiting reagent would be $S_8$

Now is posible to calculate the amount of $S_2Cl_2$ produced:

$0.124molS_8\frac{4molS_2Cl_2}{1 molS_8}\frac{135.03gS_2Cl_2}{1 molS_2Cl_2}=67.37gS_2Cl_2$

b. Mass in excess

$0.124molS_8\frac{4molCl_2}{1 molS_8}\frac{70.9gCl_2}{1 molCl_2}=35.38gCl_2$

$Excess\hspace{0.1cm}=\hspace{0.1cm}71gCl_2-35.38gCl_2=35.62 gCl_2$

C. 87%Yield

$67.37gS_2Cl_2\frac{87}{100}=58.61gS_2Cl_2$

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4 years ago

1. How does a star's life begin?

Phantasy [73]

Answer:

A star begins its life as a cloud of dust and gas (mainly hydrogen) known as a nebula. A protostar is formed when gravity causes the dust and gas of a nebula to clump together in a process called accretion. ... If a critical temperature in the core of a protostar is reached, then nuclear fusion begins and a star is born.

Explanation:

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3 years ago

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At which electrode does oxidation occur in a

Trava [24]

The right answer for the question that is being asked and shown above is that: "(2) the cathode in a voltaic cell and the anode in an electrolytic cell." At the status of electrode does oxidation occur in a voltaic cell and in an electrolytic cell is that the cathode in a voltaic cell and the anode in an electrolytic cell

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4 years ago

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3. If we remember seeing something happen, we can trust that it happened just as we think it did. True or False​

3. If we remember seeing something happen, we can trust that it happened just as we think it did. True or False