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Feliz [49]
3 years ago
7

When 10.0 g of lead are heated with 1.6 g of sulfur, 11.6 g of lead sulfide are formed. how many grams of lead sulfide form when

10.0 g of lead are heated with 3.0 g of sulfur?
Chemistry
1 answer:
nekit [7.7K]3 years ago
8 0
<span>11.6 g of lead sulfide. First, get the molar masses of lead and sulfur Lead = 207.2 Sulfur = 32.065 Now determine how many moles of each we have avaiable lead = 10.0 g / 207.2 g/mol = 0.048262548 mol sulfur = 1.6 g / 32.065 g/mol = 0.049898643 = mol This tells me that the what's being produced is PbS instead of PbS2 and that there's a very slight excess of sulfur in the original reaction. So on the 2nd reaction with the same amount of lead and twice the amount of sulfur, there will be an even greater excess of sulfur and that you'll get 11.6 g of lead sulfide.</span>
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Please help I’ll mark you as brainliest if correct
Grace [21]
The correct answer is C.
4 0
3 years ago
The empirical formula of a molecule is C2H6. In an experiment, the Molar mass of the molecule was determined to be 90.21g/mol. U
Firlakuza [10]

Answer:

C₆H₁₈

Explanation:

Let's say x is the subscript of carbon and y is the subscript of hydrogen.  We know from the empirical formula that the ratio of x to y is 2 to 6.

x / y = 2 / 6

We also know from the molar mass that:

12.01x + 1.01y = 90.21

Solving the system of equations:

2y = 6x

y = 3x

12.01x + 1.01(3x) = 90.21

12.01x + 3.03x = 90.21

15.04x = 90.21

x = 6

y = 3x

y = 18

The molecular formula is therefore C₆H₁₈.

4 0
3 years ago
A 78.0 g sample of an unknown compound contains 12.4 g of hydrogen. what is the percent by mass of hydrogen in the compound?
AleksandrR [38]
Formula to find the percent composition of an element in a compound is \frac {MolarMassOfElement}{MolarMassOfCompound}*100.

Now enter the variables into the formula.

\frac {12.4}{78.0}*100 = 15.897%
Round to 3 significant figures. 15.897% = 15.9%

The answer is 15.9% H
5 0
3 years ago
Read 2 more answers
What did Bohr’s model focus on that Rutherford’s model did not?
wlad13 [49]

Answer:

Because Rutherford's model was weak on the position of the electrons, Bohr focused on them. He hypothesized that electrons can move around the nucleus only at fixed distances from the nucleus based on the amount of energy they have. ... However, an electron could never exist in between two energy levels

3 0
3 years ago
How many grams of aluminum chloride must decompose to produce 78.3 milliliters of aluminum metal, if the density of aluminum is
Vilka [71]
1mol aluminium chloride gives 1mol aluminium and 3mol chloride
density equals mass divided by volume
d=m/v
m=v*d
=78.3*2.7
=211.41grams
7 0
4 years ago
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