Question

An object is at rest when it undergoes a constant acceleration of 13 m/s ^ 2 for 5.0 seconds. How far will it have traveled during this time?

Answer 1

Answer:

162.5 m is the distance traveled by an object.

Explanation:

Given that,

An object's constant acceleration (a) is $13m/s^2$.

The time (t) it traveled is 5 seconds.

The object is at rest that is "initial velocity" (u) is 0 m/s.

To find the distance traveled use the below formula,

$s=ut+\frac{1}{2}at^2$

Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.

Substitute the given values in the above formula,

$s=0\times5+\frac{1}{2}\times13\times 5^2$

$s=0+\frac{1}{2}\times13\times 25$

$s=0+\frac{1}{2}\times325$

s = 162.5  m

Therefore, distance traveled is 162.5 m.