Question

A sample of an ideal gas is heated, and its kelvin temperature doubles. What happens to the average speed of the molecules in the sample?

Answer 1

A sample of an ideal gas is heated, and its kelvin temperature doubles. The average speed of the molecules in the sample will increases by a factor of  $\sqrt{2}$

The root-mean square (RMS) velocity is the value of the square root of the sum of the squares of the stacking velocity values divided by the number of values. The RMS velocity is that of a wave through sub-surface layers of different interval velocities along a specific ray path.

Root mean square speed is a statistical measurement of speed.

The root mean square speed can be calculated as : V1 : $\sqrt{3 R T / Mo}$

if  temperature becomes double

let T1 is initial temperature

So ,  T2 = 2 * T1

now ,

Root mean square speed will be (V2) =  $\sqrt{(3 R (2T)) / Mo}$

                                                     = $\sqrt{2}$ * $\sqrt{3 R T / Mo}$

                                                     = $\sqrt{2}$ V1

Thus when temperature becomes double, the root mean square speed increases by a factor of  $\sqrt{2}$

To learn more about root mean square velocity here

brainly.com/question/13751940

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