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ziro4ka [17]
3 years ago
15

Heating a particular ether with HBr yielded a single organic product. Which of the following conclusions can be reached?

Chemistry
1 answer:
saw5 [17]3 years ago
8 0
Only C is correct.

A will produce either an methylbromide + alcohol

B will produce alcohol and alkyl bromide as well

C cyclic ether when reacted with HBr will only produce 1 product which has alcohol group (-OH group) on one end and Bromide group on the other end
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Today is October 31 and we view or third quarter on what date did we reserve the last new moon
Mrrafil [7]
Answer: March 21

Explanation: March 21
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3 years ago
What is the percent rate of change in function y = \((0.99)^x\)? Determine whether the function represents exponential growth or
storchak [24]

Answer: The correct answer is 1%: exponential decay.

Explanation: We are given a function:

y=(0.99)^x   ...(1)

To determine the percentage rate of change in function, we compare the given function with the general form of exponent function, which is:

y=a(1+r)^x    ...(2)

Comparing both the equations, we get:

1+r=0.99

r=-0.01

We take 'r' in percentage, so converting this above value in percentage, we get:

r=-0.01\times 100=-1\%

As the value of 'r' is negative, it means that the exponent is decaying, so the percentage rate of change in function will be 1% and it will be exponential decay.

6 0
3 years ago
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Why reactivity of elements in group 1 increase from lithium to francium?
labwork [276]

Answer:

As you go down group 1, the number of electron shells increases – lithium has two, sodium has three, and so forth. The attraction from the positive nucleus to the negative electron is less. This makes it easier to remove the electron and makes the atom more reactive.

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3 years ago
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What are the phases of the moon and how does the sun's position create them?
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4 0
4 years ago
Place each noble gas symbol in front of the appropriate partial electron configuration to create an accurate electron configurat
nydimaria [60]

The noble gas that precedes a given partial electron configuration must <em>itself </em>have an electron configuration that is complete <em>up to </em>the partial electron configuration. The noble gas's electron configuration should, when fully written out right before the partial electron configuration, give us a valid electron configuration for some element.

For the first series, the highest principal energy level has the number 4, so our noble gas should <em>at least </em>be one that is in the third period (numerically, the energy level is the same as the period number). That noble gas would be argon. The partial electron configuration given is not that of a noble gas (note: all noble gases have an electron configuration that contains <em>N</em>p⁶, where <em>N </em>= the highest principal energy level). So, the noble gas that appropriately precedes our first partial electron configuration is [Ar].

Argon's electron configuration is 1s²2s²2p⁶3s²3p⁶. Using the Aufbau Principle, 4s² would correctly follow 3p⁶. [Ar]4s²3d¹⁰4p² is equivalent to writing out 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p²; either way, this would happen to be the electron configuration of germanium.

Now that we hopefully have our fundamentals down, we can apply them to figure out the noble gases that precede the remaining partial electron configurations.

[Kr]5s²4d¹⁰5p⁵: This is the electron configuration of iodine.

[He]2s²2p⁵: This is the electron configuration of fluorine.

[Xe]6s²4f¹⁴5d¹⁰6p²: This is the electron configuration of lead.

[Ne]3s²2: This is the electron configuration of magnesium.

5 0
3 years ago
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