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Elena L [17]
3 years ago
5

How many phosphorous atoms are found in three molecules of magnesium phosphate, 3Mg3(PO4)2?

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

Since the given formula is 3Mg_{3}(PO_{4})_{2}. According to cross method formula, magnesium has +2 charge so, PO_{4} is multiplied by 2.

Thus, 1 molecule of magnesium phosphate will contain 2 atoms of phosphorus.

Therefore, three molecules of magnesium phosphate contains following number of atoms.

  • Mg = 9
  • P = 6
  • O = 24

Hence, we can conclude that there are 6 atoms of phosphorus in three molecules of magnesium phosphate, 3Mg_{3}(PO_{4})_{2}.

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miss Akunina [59]

a. 301 cg

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Explanation:

a. knowing that 1 gram (g) is equal to 100 centigrams (cg) we devise the following reasoning:

if        1 g is equal to 100 cg

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X = (3.01 × 100) / 1 = 301 cg

b. knowing that 1 kilometer (km) is equal to 1000 meters (m) we devise the following reasoning:

if         1 km is equal to 1000 m

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Kinetic energy: it is the energy possessed by the the body  due to its motion.

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To determine the name of an anion, you take the name of its element and replace the end with "ide".

<h3>What is an anion?</h3>

An anion in chemistry is a negatively charged ion.

Anions are usually formed when a non-metallic atom gains electron(s).

An anion is usually named by taking the elemental name, removing the ending, and adding “ide.

Examples of anions are as follows:

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