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3 years ago

How many phosphorous atoms are found in three molecules of magnesium phosphate, 3Mg3(PO4)2?

Chemistry

1 answer:

aleksandr82 [10.1K]3 years ago

4 0

Answer: Option (d) is the correct answer.

Explanation:

Since the given formula is $3Mg_{3}(PO_{4})_{2}$ . According to cross method formula, magnesium has +2 charge so, $PO_{4}$ is multiplied by 2.

Thus, 1 molecule of magnesium phosphate will contain 2 atoms of phosphorus.

Therefore, three molecules of magnesium phosphate contains following number of atoms.

Mg = 9

P = 6

O = 24

Hence, we can conclude that there are 6 atoms of phosphorus in three molecules of magnesium phosphate, $3Mg_{3}(PO_{4})_{2}$ .

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3 years ago

Consider a 100-gram sample of radioactive cobalt-60.

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2 years ago

If you increase the solute amount but keep the solution volume the same what

solmaris [256]

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i.e c = n/v

Hence, molarity is directly proportional to the amount of solute dissolved, and inversely proportional to the volume of solvent.

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3 years ago

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Svetlanka [38]

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3 years ago