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Elena L [17]
4 years ago
5

How many phosphorous atoms are found in three molecules of magnesium phosphate, 3Mg3(PO4)2?

Chemistry
1 answer:
aleksandr82 [10.1K]4 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

Since the given formula is 3Mg_{3}(PO_{4})_{2}. According to cross method formula, magnesium has +2 charge so, PO_{4} is multiplied by 2.

Thus, 1 molecule of magnesium phosphate will contain 2 atoms of phosphorus.

Therefore, three molecules of magnesium phosphate contains following number of atoms.

  • Mg = 9
  • P = 6
  • O = 24

Hence, we can conclude that there are 6 atoms of phosphorus in three molecules of magnesium phosphate, 3Mg_{3}(PO_{4})_{2}.

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Jaiden is writing a report about the structure of the atom. In her report, she says that the atom has three main parts and two s
yulyashka [42]

Answer:

The smallest constituent of an element is termed as an atom. According to Jaiden, an atom comprises two subatomic particles and three prime parts, however, this is incorrect as an atom comprises three subatomic particles and two main parts. The three subatomic particles are the protons, electrons, and neutrons. All these parts are smaller in comparison to an atom, thus, they are considered as subatomic particles.  

To be considered as an atom, an atom is needed only electrons and neutrons, like hydrogen exhibit one electron and one proton. On the other hand, the overall charge of the atom is not affected by the presence of neutrons, it is the subatomic particle that only enhances the mass of the atom.  

5 0
4 years ago
What is the mass of CO2 lost at 20 min from the limestone sample?
harkovskaia [24]

Answer:

The mass, CO2 and CO3 from the limestone sample is discussed below in details.

Explanation:

(A) mass loss of sample of limestone after 20 min

= 0.8437g-0.5979g = 0.2458 g

From the given reaction of limestone, 2 mol of the sample gives 2 moles of CO 2.

Therefore  

184.4 g ( molar mass of limestone) gives2× 44 g of carbon dioxide.

1 g of sample gives 88/184.4 g of carbon dioxide

Hence 0.2458 g sample gives

= 88/184.4 × 0.2458 g = 0.117 g carbon dioxide

(B) mole of CO 2 lost = weight/ molar mass

= 0.117 g / 44 g/mol =0.0027 mole

(C). 1 mol of limestone contain 2 mol of carbonate ion

From the reaction we know that carbonate ion of limestone is converted into carbondioxide

Hence lost carbonate ion = 0.2458 g

(D) we know that

1 mol limestone contain 1mol CaCO​​​ 3

Hence in sample present CaCO​​​ 3

= 1mole / 184.4 g × 0.8437 g= 0.00458 mol CaCO​​​3

8 0
3 years ago
What are the oxidation numbers of K, Cl, and O in KClO,?
Tatiana [17]

Answer: Oxidation number of chlorine in potassium chlorate...

so, oxidation state of chlorine in potassium chlorate is +1. and yea!!

Explanation: hope this help

4 0
3 years ago
You've made the hypothesis that the less rainfall a cactus plant gets, the taller it will grow, since cactuses like dry conditio
Leviafan [203]

A. the height of the cactus plants

Explanation:

The dependent variable in this experiment designed to test this hypothesis is the height of the cactus plants.

In a hypothesis statement, we can always deduce the dependent and independent variables.

  • Independent variables do not rely on other variables. They are usually the cause of the phenomenon observed in an experiment. In this experiment, it is the rainfall on the cactus plant.
  • Dependent variable is that variable that relies on the independent variable. It is usually the effect of changes in independent variable.
  • The height of the cactus plant depends on the amount of rainfall in an area.

learn more:

Controlled experiment brainly.com/question/1621519

#learnwithBrainly

5 0
3 years ago
What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of soluti
puteri [66]

Answer: The concentartion of solution will be 0.224 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute =\frac{\text{Given mass}}{\text{Molar mass}}=\frac{10.0g}{162.2g/mol}=0.0616moles

{V_s} = volume of solution in ml = 275 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.0616\times 1000}{275ml}=0.224mole/L

Therefore, the concentration of solution will be 0.224 M

7 0
4 years ago
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