Answer:
pH = 10.75
Explanation:
To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]
Using the equation:
pH = 14 - pOH
We can find the pH of the solution.
The molarity of Ca(OH)₂ is 2.8x10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8x10⁻⁴M = 5.6x10⁻⁴M
pOH is
pOH = -log 5.6x10⁻⁴M
pOH = 3.25
pH = 14-pOH
<h3>pH = 10.75</h3>
Explanation:
Monitor the temperature of the water with the thermometer. Stop heating the water once it nears the boiling point of 100 degrees Celsius. Add copper(II) sulfate and stir until the heated solution is saturated. When the solution is saturated, copper(II) sulfate will not dissolve anymore
<span>Saturated sodium chloride
is used to transfer the product rather than water since it is not polar and
rinsing the product with water would revert any 4-methylcyclohexene back to
4-methylcyclohexanol in the Hickman Head and thus lowering the percent yield;
using water would shift the equilibrium towards the reactants. Also
sodium chloride removes the small amount of phosphoric acid and also a small
amount of water. If one were to add water, both 4-methylcyclohexene and
phosphoric acid are partially soluble making difficult to remove the water
later; sodium chloride makes the water less reactive so easier to remove by
making the aqueous later more polar.</span>
