Question

How can i solve this equation

Answer 1

Answer:

D. -1.44 and 2.44

Step-by-step explanation:

$f(x) = 2 {ax}^{2} + (3 - b)x + 7$

is equal to:

$g(x) = (a - 1) {x}^{2} + 2bx + 7$

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➡️ $- 2 {x}^{2} + 2x + 7 = 0$

➡️ $Δ = {b}^{2} - 4ac = 4 - 4 \times 7 \times ( - 2) = 60 = \sqrt{Δ} = 7.746$

➡️ $x = \frac{ - b± \sqrt{Δ} }{2a} = \frac{ - 2± 7.746}{ - Δ}$

➡️ $x_{1} = \frac{ - 2 + 7.746}{ - 4} = - 1.44$

➡️ $x_{2} = \frac{ - 2 - 7.746}{ - 4} = 2.44$