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Kitty [74]
3 years ago
9

Isabelle has a bag of apples that contains green and red apples. She gives 1 green apple and 2 red apples to each of her 5 frien

ds and has no apples left over.
Isabelle’s bag originally contained _____ apples.

Answer choices:

3 apples
5 apples
8 apples
15 apples
Mathematics
2 answers:
Lina20 [59]3 years ago
5 0

Answer:

15 APPLES.

DOUBLE 5 EQUALS 10

10 PLUS 5 EQUALS 15

Gelneren [198K]3 years ago
3 0

Answer:

d)15 apples

Step-by-step explanation:

We know that she gives 2 red apples and 1 green apple to 5 friends and has no more left over.  you add 2+1=3 Then you multiply 3x5=15.

Hope this helps! Have a great day ahead. Tell me if I'm wrong :) Stay Safe <3

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Read 2 more answers
The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
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3 years ago
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You can also tell if a linear equation is proportional if the equation has an constant after the x (for example y=2x+6)

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