X^2 - 5xy + 6y^2 = <span>(x - 3y)(x - 2y)
answer is </span><span>C) (x - 3y)(x - 2y)
hope that helps</span>
The Center Pays<span> $0.002 For </span><span>Each Kilogram</span>
Answer:
a. y^ -1 = e^x +2
Step-by-step explanation:
y = ln (x-2)
Exchange x and y
x = ln (y-2)
Solve for y
Raise each side with a base of e
e^ x = e^(ln(y-2)
e^x = y-2
Add 2 to each side
e^x +2 =y
We know that the building must form a right angle with the ground, so the triangle formed by the ladder, the wall, and the distance between the base of the ladder and the wall is a right triangle. We can use the Pythagorean theorem to find the distance the ladder is from the building.
a^2 + b^2 = c^2
We know that the ladder is the hypotenuse because it is opposite the right angle.
a^2 + b^2 = 20^2
Substitute the length of the other side and solve.
a^2 + 17^2 = 20^2
a^2 + 289 = 400
a^2 = 111
The distance from the wall to the bottom of the ladder is the square root of 111 or approximately 10.5357 feet
Answer:
tanI = 
Step-by-step explanation:
We require to calculate GH using Pythagoras' identity in the right triangle.
GH² + GI² = HI²
GH² + 5² = (
)²
GH² + 25 = 95 ( subtract 25 from both sides )
GH² = 70 ( take square root of both sides )
GH = 
Then
tanI = 
= 
=
