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DiKsa [7]
3 years ago
8

PLS HELPPPP!!! Its Due today , i need helpp!! There is a sequence of rigid transformations that takes A to A’, B to B’, and C to

C’. The same sequence takes D to D’. Draw and label D’ :

Mathematics
1 answer:
stiv31 [10]3 years ago
4 0

Answer:

Is in the attachment.

<em>Hope it helps you</em>

<em>If you have any questions just ask me </em>

<em>If you think my answer is the best mark me as brainliest</em>

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SOMEONE PLEASE HELP WILL MARK BRAINLIEST PLEASE EXPLAIN
zalisa [80]

Answer:

a. (x+5)^2 = 49

b. (x+7)^2 = (x+1)^2

Step-by-step explanation:

So the term "a number" is always going to be x. input x into the sentences. "X plus five, then squared, is forty-nine". when they do "is __", that means equal to. In the second question, seven more than x is x + 7 (the two numbers are interchangeable here). Equivalent also means equal. hope this helped :)

4 0
3 years ago
Read 2 more answers
The function g has an inverse. The function g − 1 determines the number of folds needed to give the folded paper a thickness of
Amanda [17]

Answer:

\mathbf{g^{-1} (t) = log _2  \ 20 \ t}

Step-by-step explanation:

Here is the full question

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times. We'll assume we can make "perfect folds," where each fold makes the folded paper exactly twice as thick as before - and we can make as many folds as we want.

Write a function g that determines the thickness of the folded paper (in mm) in terms of the number folds made, n. (Notice that g(0) 0.05,)

g(n )= (05)2^n

The function g has an inverse. The function g⁻¹ determines the number of folds needed to give the folded paper a thickness of t mm. Write a function formula for g⁻¹).

<u>SOLUTION:</u>

If we represent g(n) with  t;

Then

\mathbf{t = (0.05)2^n} \\ \\ \mathbf{\dfrac{t}{0.05} = 2^n} \\ \\ \mathbf{\dfrac {100 \ t }{ 5} = 2^n} \\  \\ \mathbf{20 t = 2^n}

Taking logarithm of both sides; we have :

\mathbf{log (20 t) = n log 2}    \ \ \    \mathbf{(since  \ ,  log  \ a^b = b \ log \ a) }  \\ \\ \mathbf{n =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) = log _2  \ 20 \ t}

4 0
4 years ago
I need help...WILL GIVE BRAINLIEST !!!!!
Aliun [14]

Answer:

Step-by-step explanation:

48 is preimeter

96 is the area

Make me brainliest

4 0
3 years ago
Can anyone help check if my calculation is correct or wrong?
8_murik_8 [283]
It’s correct good job
6 0
4 years ago
Read 2 more answers
Find the sum of these polynomials<br> (x^8-x+7)+(9x^8+6)=
DerKrebs [107]
<span><span><span><span>I think is this 9<span>x8</span></span>+<span>x7</span></span>−x</span>+<span>13</span></span>
8 0
3 years ago
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