Answer:
The velocity of the 4.00 kg object after the collision is 12 m/s.
Explanation:
Given that,
Mass of object
Velocity of object
Mass of another object
Velocity of another object
We need to calculate the relative velocity
The relative velocity is 8 m/s in west before collision.
We know that,
In one dimensional elastic collision, the relative velocity before collision equals after collision but with opposite sign.
So, The relative velocity after collision must be 8 m/s in east.
So, The object of 6.00 kg is going 20 m/s and the object of 4.00 kg is slows down to 12 m/s.
Hence, The velocity of the 4.00 kg object after the collision is 12 m/s.
The product of an object's mass and velocity is B.momentum.
<span>♡♡Hope I helped!!! :)♡♡
</span>
2.14x 1022 kg
the 22 is a xponet of ten
First let's find the time it takes for the first ball to land:
Acceleration is a=-g so vertical velocity is V=-gt + V1sin(30).
Position is thus
S=(-1/2)gt^2 +V1t sin(30).
Solving for t gives
t=2V1sin(30)/g
The second ball has the same position function except for the new velocity, which is given by
V2=2V1. Putting this in and solving for t2 gives
t2=4V1sin(30)/g.
It takes twice as long for the second ball to land on the ground.
The horizontal distance of ball 1 is S1 = V1t cos(30). Again we look at ball 2's distance by substituting V2=2V1 and get
S2 = 2V1t2 cos(30).
Note here I put in t2 since it will fly for that amount of time. But we already saw that
t2 = 2t1
So S2=4V1 cos(30)
That is the second ball goes 4 times further than the first one. This is because it is going twice as fast along both the horizontal and the vertical. It moves horizontally twice as fast for twice as long.
Heredity is passing on physical traits to your offspring and if you had parents that had a disease it can effect you that can later affect your physical fitness