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torisob [31]
3 years ago
9

Báo cáo thực hành

Physics
1 answer:
pishuonlain [190]3 years ago
4 0

Answer:

which language is this

Explanation:

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A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.25 kg to a friend standing in front of him
juin [17]

Answer:

The velocity of the student has after throwing the book is 0.0345 m/s.

Explanation:

Given that,

Mass of book =1.25 kg

Combined mass = 112 kg

Velocity of book = 3.61 m/s

Angle = 31°

We need to calculate the magnitude of the velocity of the student has after throwing the book

Using conservation of momentum along horizontal  direction

m_{b}v_{b}\cos\theta= m_{c}v_{c}

v_{s}=\dfrac{m_{b}v_{b}\cos\theta}{m_{c}}

Put the value into the formula

v_{c}=\dfrac{1.25\times3.61\times\cos31}{112}

v_{c}=0.0345\ m/s

Hence, The velocity of the student has after throwing the book is 0.0345 m/s.

3 0
3 years ago
A student adds ice to 150 mL of water. She observes that the temperature of the water decreases after 10 minutes. Which statemen
Step2247 [10]

Answer:

3- kinetic energy was transferred from the water to the ice

Explanation:

the kinetic energy in this situation is the molecules vibrating so the molecules in the ice absorb it and make the molecules not vibrate so it gets colder

3 0
3 years ago
If a galaxy is located 200 million light years from Earth, what can you conclude about
timofeeve [1]

Answer:

D

Explanation:

It's quite simple actually, you see, what light years basically means is how many years light takes to travel from point a to point b. So here it says that a galaxy is 200 million light years away. So since that light is 200 million years away, it would take 200 million years until that light reaches us.

5 0
4 years ago
an athlete runs 300 m up a hill at a steady speed of 3.0 m/s. She then immediately runs the same distance at 6.0 m/s . What is h
mina [271]

Answer:

4.0 m/s

Explanation:

In the first part of the run, the athlete runs a distance of

d_1 = 300 m

at a speed of

v_1 = 3.0 m/s

So, the time he/she takes is

t_1 = \frac{d_1}{v_1}=\frac{300}{3.0}=100 s

In the second part of the run, the athlete covers an additional distance of

d_2 = 300 m

with a speed

v_2 = 6.0 m/s

So, the time taken in this second part is

t_2 = \frac{d_2}{v_2}=\frac{300}{6.0}=50 s

So, the total distance covered is

d = 300 m + 300 m = 600 m

And the total time taken

t = 100 s + 50 s = 150 s

Therefore, the average speed for the entire trip is

v=\frac{d}{t}=\frac{600}{150}=4.0 m/s

4 0
4 years ago
You are piloting a plane traveling 160 km/h. A child is seated behind you in the airplane. Describe the speed of the child relat
Elena-2011 [213]

Answer:

C

Explanation:

they are still in the same plane witch means they going the same speed

3 0
2 years ago
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