The minimum force required to lift the box at constant velocity is determined as 274.4 N.
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Minimum force required</h3>
The minimum force required to lift the box at constant velocity is the tension in one of the pulleys, and the magnitude is calculated as follows;
2T = mg
where;
- m is mass of the box
- T is the minimum force required
2T = mg
T = mg/2
T = (56 x 9.8)/2
T = 274.4 N
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Answer:
Ion channels in the plasma membrane of the receiving neuron open
Explanation:
Ionotropic receptors are protein structures of the neuronal plasma membrane that function as specific ion channels for certain ions. Depending on the type of ion involved is the nature of the effect that occurs when these channel receptors open. Being ionic channels, these types of receptors participate in the rapid, exciting or inhibitory responses that neurons give.
For now we will refer only to ionotropic excitatory receptors which, by allowing the passage of ions such as sodium or calcium, produce a decrease in membrane potential (hypopolarization). This increases the probability of generating action potentials in the neuron.
To these, like other types of receptors, specific neurotransmitters are attached, which causes their activation and opening.
In addition to presenting an ionic channel in their structure, these receptors have a site where a specific neurotransmitter (binding site to the neurotransmitter) binds. But there are also sites of binding to other molecules, which without causing their opening modify, however, the effect of the neurotransmitter. That is, the receptors can be modulated by other molecules.
A typical example of an ionotropic receptor is the cholinergic receptor (its specific neurotransmitter is acetylcholine, ACh) of the nicotinic subtype found in the skeletal neuromuscular synapse. Part A of the scheme. When ACh binds to the receptor, the channel opens causing sodium ion (Na +) to enter, causing hypopolarization (or depolarization) at that point. The name of this type of receptors derives from the fact that they can be identified with nicotine, a substance that specifically binds to them.
Answer:
The work done required on the coin during the displacement is 21.75 w.
Explanation:
Given that,
A coin slides over a friction-less plane i.e friction force = 0.
The co-ordinate of the given point is (1.40 m, 7.20 m).
The position vector of the given point is represented by 
.
The displacement of the coin is
The force has magnitude 4.50 N and its makes an angle 128° with positive x axis.
Then x component of the force = 4.50 cos128°
The y component of the force = 4.50 sin128°
Then the position vector of the force is
We know that,
work done is a scalar product of force and displacement.
=(-2.77×1.40+ 3.56×7.20) w
=21.75 w
The work done required on the coin during the displacement is 21.75 w.
Answer: well if it isnt moving, then there would not be any potentiol energy. Sothe answer is 0. I hope this helps :) Thank you. Plz mark brainliest.
Explanation:
Answer:
A. Attractive
B. ( μ₀I² ) / ( 2πd )
Explanation:
A. We know that currents in the same direction attract, and currents in the opposite direction repel, according to ampere's law. In this case the current in the two wires are flowing in the same direction, and hence the force between the two wires are attractive.
B. Suppose that two wires of length 
and 
both carry the current 
in the same direction ( given ). In the presence of a magnetic field produced by wire 1, a force of magnitude m say, is experienced by wire 2. The magnitude of the magnetic field produced by wire 1 at distance say d, from it's axis, should thus be the following -
= μ₀I / 2πd
The force experienced by wire 2 should thus be -
= I( 
)
= I 
Sin( 90 )
= I ( μ₀I / 2πd )
Therefore the force per unit length experienced by wire 2 toward wire 1 should be ...
( / ) = ( μ₀I² ) / ( 2πd ) ... which is our solution
