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FromTheMoon [43]
3 years ago
15

When neurotransmitter molecules bind to receptors in the plasma membrane of the receiving neuron

Physics
1 answer:
Maru [420]3 years ago
4 0

Answer:

Ion channels in the plasma membrane of the receiving neuron open

Explanation:

Ionotropic receptors are protein structures of the neuronal plasma membrane that function as specific ion channels for certain ions. Depending on the type of ion involved is the nature of the effect that occurs when these channel receptors open. Being ionic channels, these types of receptors participate in the rapid, exciting or inhibitory responses that neurons give.

For now we will refer only to ionotropic excitatory receptors which, by allowing the passage of ions such as sodium or calcium, produce a decrease in membrane potential (hypopolarization). This increases the probability of generating action potentials in the neuron.

To these, like other types of receptors, specific neurotransmitters are attached, which causes their activation and opening.

In addition to presenting an ionic channel in their structure, these receptors have a site where a specific neurotransmitter (binding site to the neurotransmitter) binds. But there are also sites of binding to other molecules, which without causing their opening modify, however, the effect of the neurotransmitter. That is, the receptors can be modulated by other molecules.

A typical example of an ionotropic receptor is the cholinergic receptor (its specific neurotransmitter is acetylcholine, ACh) of the nicotinic subtype found in the skeletal neuromuscular synapse. Part A of the scheme. When ACh binds to the receptor, the channel opens causing sodium ion (Na +) to enter, causing hypopolarization (or depolarization) at that point. The name of this type of receptors derives from the fact that they can be identified with nicotine, a substance that specifically binds to them.

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Is gravity a force ?
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Answer:

Gravity ( gravity , weight, traction force) is the force acting on any body on or near the surface of the celestial body directed at its center. Gravity, that is, the force with which the earth , moon , planets, and other celestial bodies or their systems act on other bodies, is theoretically exercised at any distance, but is practically examined on the surface of these bodies as well as at short distances.

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3 years ago
Which is the best procedure to make a permanent magnet?
notka56 [123]

placing a magnetically hard material in a strong magnetic field

7 0
3 years ago
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A machinist with normal vision has a near point at 25 cm. The machinist wears eyeglasses in order to do close work. The power of
Alik [6]

Answer:

17.4 cm

Explanation:

Power of lens = +1.75 diopters

Focal length of lens

f=\frac{100}{1.75}=\frac{400}{7}

This is a convex lens as focal the diopter given is positive which makes the focal length positive. Image distance will be negative.

v = -25

\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\\Rightarrow \frac{1}{-25}-\frac{1}{u}=\frac{1}{\frac{400}{7}}\\\Rightarrow -\frac{1}{u}=\frac{7}{400}+\frac{1}{25}\\\Rightarrow \frac{1}{u}=-\frac{7}{400}-\frac{1}{25}\\\Rightarrow \frac{1}{u}=-0.0575\\\Rightarrow u=-17.4\ cm

∴ The new near point is 17.4 cm

7 0
3 years ago
Name the type of particle formed by covalent bonds
jasenka [17]
Molecules and polyatomic ions are formed by covalent bonds.
6 0
3 years ago
A copper rod of cross-sectional area 11.6 cm2 has one end immersed in boiling water and the other in an ice-water mixture, which
julia-pushkina [17]

Answer:

0.686 g of ice melts each second.

Solution:

As per the question:

Cross-sectional Area of the Copper Rod, A = 11.6\ cm^{2} = 11.6\times 10^{- 4}\ m^{2}

Length of the rod, L = 19.6 cm = 0.196 m

Thermal conductivity of Copper, K = 390\ W/m.^{\circ}C

Conduction of heat from the rod per second is given by:

q = \frac{KA\Delta T}{L}

where

\Delta T = 100^{\circ} - 0^{\circ} = 100^{\circ}C = temperature difference between the two ends of the rod.

Thus

q = \frac{390\times 11.6\times 10^{- 4}\times 100}{0.196} = 228.48\ J/s

Now,

To calculate the mass, M of the ice melted per sec:

M = \frac{q}{L_{w}}

where

L_{w} = Latent heat of fusion of water = 333 kJ/kg

M = \frac{228.48}{333\times 10^{3}} = 6.86\times 10^{- 4}\ kg = 0.686\ g

5 0
3 years ago
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