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Mrac [35]
3 years ago
10

How many toothpicks will be required to make the fith row ?

Mathematics
1 answer:
hammer [34]3 years ago
6 0

Answer:

6

Step-by-step explanation:

I am thinking it is 6 because you can just look at b and it looks the same

so I think it would be the same answer

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3 years ago
What is "house flipping?" a. The process of transferring ownership of a house from one person to another. b. The process of buyi
nalin [4]

Answer:

The answer is B, i believe

Step-by-step explanation:

House flipping is usually when you buy s house and renovate it to make it look nicer and then selling it for more to make a profit from that.

5 0
3 years ago
A parabola intersects the x-axis at x=−4 and x=8.
cupoosta [38]

Answer:

C. x=2

Step-by-step explanation:

The axis of symmetry divides the parabola into two equal parts. FRom point x=-4 to x=8, the difference is 12 units and the centre is6 units on each side. Using a number line, the axis of symmetry is at point x=2

5 0
3 years ago
Read 2 more answers
F(x)=2x <br> 2<br> −x+9<br> \text{Find }f(4)<br> Find f(4)
Artemon [7]

Answer:

37

Step-by-step explanation:

f(x)=2x²−x+9

f(4)= 2(4)²-4+9

= 32-4+9

= 37

8 0
3 years ago
How do you find a vector that is orthogonal to 5i + 12j ?
Rashid [163]
\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\&#10;slope=\cfrac{a}{{{ b}}}\qquad negative\implies  -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\&#10;-------------------------------\\\\

\bf \boxed{5i+12j}\implies &#10;\begin{array}{rllll}&#10;\ \textless \ 5&,&12\ \textgreater \ \\&#10;x&&y&#10;\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}&#10;\\\\\\&#10;slope=\cfrac{12}{{{ 5}}}\qquad negative\implies  -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}&#10;\\\\\\&#10;\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}&#10;\\\\\\&#10;\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}&#10;\\\\\\&#10;\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}
4 0
3 years ago
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