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Mrac [35]
3 years ago
10

How many toothpicks will be required to make the fith row ?

Mathematics
1 answer:
hammer [34]3 years ago
6 0

Answer:

6

Step-by-step explanation:

I am thinking it is 6 because you can just look at b and it looks the same

so I think it would be the same answer

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What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
The sum of a number X and four all divided by three
sergey [27]

If you are looking for the expression, that would be (x+4)/3

4 0
2 years ago
Read 2 more answers
Please help me asap<br><br>​
dimaraw [331]
Okay so basically 1 + 5 = 180
and if we know 1 = 124 we can assume 5 = 56
and 5 = 4 SOOOO
4 = 56
4 0
3 years ago
What is 18/25 as a decimal
Serga [27]

Answer: 0.72

Step-by-step explanation:

Hope that helps :)

4 0
3 years ago
Read 2 more answers
Determine whether the ratios 35 feet every 15 seconds and 7 feet every 2 seconds are equivalent.
murzikaleks [220]

Answer:

Step-by-step explanation:

Find the rate of those two statements:

28 ÷ 16 = 1.75

1.75 ft per seconds

7 ÷ 4 = 1.75

1.75 ft per seconds

Two statements have the same rate, therefore 28 feet every 16 seconds and 7 feet every 4 seconds are equivalent

5 0
1 year ago
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