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Amiraneli [1.4K]
2 years ago
12

If A (-1,3) , B (7-3) and C (4, 1) are three points, show that AB =2BC

Mathematics
2 answers:
Marysya12 [62]2 years ago
7 0

{ab}^{2}  =  \sqrt{( {7 - ( - 1))}^{2} +(  { - 3 - 3)}^{2} }  \\  =  \sqrt{ {8}^{2}  + { - 6 }^{2}  }  \\  =  \sqrt{64 + 36 }  \\  =  \sqrt{100 }  \\ ab = 10

{bc}^{2}  =  \sqrt{( {4 - 7)}^{2} +  {(1 - ( - 3))}^{2}  }  \\  =  \sqrt{{ - 3}^{2}  +  {4}^{2} }  \\  =  \sqrt{  9 + 16}  \\  =  \sqrt{25}  \\ bc = 5

Ber [7]2 years ago
5 0

Answer:

See the attachment for explanation

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vichka [17]

Answer:

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Step-by-step explanation:

divide coefficients and subtract exponents

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[Systems of equations] (/20) 1. Suppose the coefficient matrix of a system of linear equations has a pivot position in every row
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Answer:

The system is consistent because the rightmost column of the augmented matrix is not a pivot column.

Step-by-step explanation:

It is given that the coefficient of the matrix of a linear equation has a pivot position in every row.

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For any m x n augmented matrix of any system, if its co-efficient matrix has a pivot position in every row, then there will never be a row of the form [0 .... 0 b].

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-(14-2y) +3y+26 how do i find y
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Y is behind 2 its in plain sight   
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Which best describes the shape of this distribution?
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p(1)=a \times 1^4+b \times 1^3 + c \times 1^2+ d \times 1+e \\&#10;p(-1)=a \times (-1)^4 + b \times (-1)^3 + c \times (-1)^2 + d \times (-1)+e \\ \\&#10;p(1)=a+b+c+d+e \\&#10;p(-1)=a-b+c-d+e \\ \\&#10;p(1)=0 \\&#10;p(-1)=0 \\ \\ \hbox{add both equations:} \\&#10;a+b+c+d+e=0 \\&#10;\underline{a-b+c-d+e=0} \\&#10;2a+2c+2e=0 \\&#10;2(a+c+e)=0 \\&#10;a+c+e=0 \\ \\&#10;\hbox{substitute 0 for a+c+e in the first equation:} \\&#10;a+b+c+d+e=0 \\&#10;(a+c+e)+b+d=0 \\&#10;0+b+d=0 \\&#10;b+d=0 \\ \\&#10;\boxed{a+c+e=b+d=0} \\&#10;\hbox{proved } \checkmark
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