According to the following reaction, the volume of KCl solution required to react with 50ml of 0.21M Pb(NO3)2 solution is 86mL (based on chemical equation).
<h3>What is chemical equation? </h3>
It is an equation that make use of chemical formulae and symbols to represent chemical reactions. The left-hand side of a chemical equation represents the reactants and the right-hand side represents the products.
How to calculate the volume of KCl solution using chemical equation?
First, let's write the chemical equation
2KCl + Pb(NO₃)₂ -> PbCl₂ + 2KNO₃
Given from the question
Molarity of Pb(NO₃)₂ = 0.210M
Volume of Pb(NO₃)₂ solution = 50mL = 50 / 1000 = 0.05L
Molarity of Pb(NO₃)₂ solution = Number of moles of Pb(NO₃)₂ / volume of solution in L
0.210M = Number of moles of Pb(NO₃)₂ / 0.05L
Number of moles of Pb(NO₃)₂ = 0.0105 mol
Using stoichiometric coefficients from the chemical equation above
1 mol Pb(NO₃)₂ requires 2 moles of KCl
so, 0.0105 mol Pb(NO₃)₂ requires (2 * 0.0105) moles KCl = 0.021mol KCl
Number of moles of KCl = 0.021 mol
Molarity of KCl solution = 0.244M
Molarity of KCl solution = Number of moles of KCl / Volume of KCl solution in L
0.244 = 0.021 / volume of solution in L
Volume of KCl solution = 0.021 / 0.244
= 0.0861 (rounded) L * 1000 mL
= 86mL
Therefore, the volume of KCl solution required is 86mL.
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