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yKpoI14uk [10]
3 years ago
6

A circular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane

of the loop and the magnetic flux through the loop is 8.60 10-3 T · m2, what is the strength of the magnetic field?
Physics
1 answer:
Mama L [17]3 years ago
4 0

Answer:

Magnetic field, B = 0.199 T

Explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop, \phi=8.6\times 10^{-3}\ T/m^2

The magnetic flux linked through the loop is :

\phi=B.A

\phi=BA\ cos\theta

Here, \theta=0

B=\dfrac{\phi}{A}

or

B=\dfrac{\phi}{\pi r^2}

B=\dfrac{8.6\times 10^{-3}}{\pi (0.117 )^2}

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.

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