Answer:
To obtain the grams of fat that the ground round has, knowing that it weighs 1.33 pounds we must pass this value to grams. Since 1 pound equals 453.59 grams, 1.33 pounds equals 603.27 (453.59 x 1.33).
Now, to obtain 29 percent of 603.27, we must make the following calculation: 603.27 / 100 x 29, which gives a total of 174.94 grams.
In this way, your reasoning is correct and it is probably a mistake in the book.
Answer:
IV
Explanation:
The complete question is shown in the image attached.
Let us call to mind the fact that the SN1 mechanism involves the formation of carbocation in the rate determining step. The order of stability of cabocations is; tertiary > secondary > primary > methyl.
Hence, a tertiary alkyl halide is more likely to undergo nucleophilic substitution reaction by SN1 mechanism since it forms a more stable cabocation in the rate determining step.
Structure IV is a tertiary alkyl halide, hence it is more likely to undergo nucleophilic substitution reaction by SN1 mechanism.
The hybrid orbital of this molecule is
. Hence, option C is correct.
<h3>What is hybridisation?</h3>
Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
In this compound,
a hybrid orbital makes I-O bonds. Due to
hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of
the ion is pyramidal.
The hybrid orbital of this molecule is
. Hence, option C is correct.
Learn more about hybridisation here:
brainly.com/question/23038117
#SPJ1
Answer;
= 64561.95 g/mole
Explanation;
mass of Fe in 100g = .346g
= .346 / 55.8452 moles
= 0.0061957 moles
These represent 4 moles of Fe in the molecule so moles of hemaglobin
= 0.0061957/4
= 0.0015489 moles
these are in 100 g so mass of 1 mole = 100 / 0.0015489
= 64561.95 g / mole
molar mass of hemoglobin = 64561.95 g/mole
Answer:
18 years old or when they become mature.
Explanation: