Answer:
Key Takeaways: Isotopes
Isotopes are samples of an element with different numbers of neutrons in their atoms.
The number of protons for different isotopes of an element does not change.
Not all isotopes are radioactive. Stable isotopes either never decay or else decay very slowly. ...
When an isotope decays, the starting material is the parent isotope.
Explanation:
 
        
             
        
        
        
(C) 200 N
Explanation:
The acceleration due to gravity on earth  is given by
 is given by

where  = universal gravitational constant
 = universal gravitational constant 
 = mass of the earth
 = mass of the earth 
 = radius of the earth
 = radius of the earth 
Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity  is
 is



or

If we multiply both sides by Superman's mass, we get his weights on both planets:


 
        
             
        
        
        
Deposition is geological process of sediments, soil and rocks that are added to land-form or land mass. Wind, ice, water, and gravity transport weathered surface material, which, at the loss of enough kinetic energy in the fluid, is deposited. Technically  Building up layers of sediment.
hope this helps
:D
 
        
             
        
        
        
Answer:
You have just driven across the Cold front.
Explanation:
Weather Front:
In Meteorology, weather fronts are simply boundaries between two air masses of different densities. There are four weather fronts and one of them is cold front and other fronts are warm front, stationary front and occluded front. 
Cold Front:
In Meteorology, cold front is a boundary of cold air mass that is advancing under the warm air mass.
In our scenario, as the driver was moving in the west and he listened on radio, the next country on north is under tornado warning. So, when he passed the cold front, he experienced the conditions described. 
 
        
             
        
        
        
<span>Ans : Bernoulli's principle states for incompressible non-viscous flow that
p/Ď + gâ™h + (1/2)â™v² = constant
Evaluate the equation along a stream line from liquid surface of the reservoir (1) to the inlet of the pipe
pâ‚/Ď + gâ™hâ‚ + (1/2)â™v₲ = pâ‚‚/Ď + gâ™hâ‚‚ + (1/2)â™v₂²
=>
vâ‚‚ = âš[ 2â™(pâ‚-pâ‚‚)/Ď + 2â™gâ™(hâ‚-hâ‚‚) + v₲ ]
lets make some assumptions:
- the pressure at the liquid surface is equal to the atmospheric pressure
pâ‚ = 1atm = 101325Pa
- the velocity of the liquid at the surface (that is the speed at which the liquid level in reservoir decreases) is quite small, so it may be ignored:
v₠≠0
So
vâ‚‚ = âš[ 2â™(pâ‚-pâ‚‚)/Ď + 2â™gâ™(hâ‚-hâ‚‚) ]
The height difference is fixed. So the only variable remaining is the pressure in the pipe. As higher it is as lower the velocity in the pipe is.
So you get the maximum velocity for the minimum pressure.
Since pressure cannot drop below zero this is
pâ‚‚ = 0
Therefore
vâ‚‚max = âš[ pâ‚/Ď + gâ™(hâ‚-hâ‚‚) ]
= âš[ 2â™101325Pa/1000kg/mÂł + 2â™9.81m/s²â™12m ]
= 20.93m/s</span>