the focal length <span> is much more decent for a concave, and also worse</span><span> for a convex mirror. When the image that is given, distance is good and decent, images are always on the same area of the mirror as the object given , and it is not fake. images distance is </span>never positive <span>, the image is on the oppisite side of the mirror, so the image must be virtual.</span>
There is no SI "base unit" of density.
(Any unit of mass) divided by (any unit of volume) is
a valid unit of density.
The units of density that are seen most often are
(gram per cm³) and (kgm per meter³) .
Answer:

Explanation:
Use the velocity formula to solve

In this question, you are given velocity
, and you are given a distance,
. Time in this question is what you'll need to find.
Start by rearranging the velocity formula, to isolate for t.

Start by multiplying both sides by t

Then divide both sides by v.

Now that you've isolated for time, sub in your values and calculate.


Solution is in attachment ~
I hope that you got what you were looking for, and if there's different data then go through the same procedure, using same formula with different values and you will get your answer ~
