The equation of the first line can be written in point-slope form as
.. y = 3(x +1) -8
or
.. 3x -y = 5
The equation of the second line can be written in 2-point form as
.. y = (-1-3)/(10-(-6))*(x +6) +3
.. y = (-1/4)(x +6) +3
or
.. x +4y = 6
A graph shows the solution to this system is (x, y) = (2, 1).
_____
The second equation can be used to write an expression for x:
.. x = 6 -4y
This can be substituted into the first equation.
.. 3(6 -4y) -y = 5
.. 18 -13y = 5 . . . . . . . collect terms
.. 13 = 13y . . . . . . . . . add 13y-5
.. 1 = y . . . . . . . . . . . . divide by 13
From the above equation for x
.. x = 6 -4*1 = 2
Answer:
For question 3, you would just add 2 to the x values and subtract 2 from the y values, so it would be:
J' (-2, 5)
K' (2, 6)
L' (1, 2)
M' (-3, 1)
For question 4 you would subtract 7 from the x values and 6 from the y values, and that would be:
W' (-6, 1)
X' (-1, -1)
Y' (-3, -6)
Z' (-8, -4)
For question 9 you would end up with:
X' (6, -5)
Y' (7, 1)
Z' (4, 0)
For question 10 you would end up with:
Q' (-1, 2)
R' (1, 7)
S' (-2, 6)
T' (-4, 1)
For question 11 you would end up with:
L' (4, 1)
M' (8, 5)
N' (6, 7)
P' (2, 3)
For question 12 you would end up with:
G' (6, -7)
H' (6, -4)
I' (1, -7)
Hope this is what you were looking for!
Step-by-step explanation:
Answer:
option C. 
option D. 
option F. 
Step-by-step explanation:
step 1
we know that
In the right triangle JKL


so


step 2


so


step 3




Answer:
143
Step-by-step explanation:
Substitute n=3 into the problem
6(
)-2(
) +3-4
Then figure out squared and power by 3
6(27)-2(9)+3-4
Next multiply
162-18+3-4
Finally, add and subtract
144+3=147
147-4=143