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3 years ago

I need all solutions

Chemistry

1 answer:

marshall27 [118]3 years ago

6 0

Answer:

Answer is in the attachment

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Which element is present in all organic compounds?

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Carbon and Hydrogen are present in all organic compounds !

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A certain reaction has an activation energy of 67.0 kJ/mol and a frequency factor of A1 = 4.20×1012. What is the rate constant,

MrRa [10]

Answer:

K = 7.00

Explanation:

1) Arrhenius equation

Arrhenius equation shows the relation between activation energy, temperature, and the equilibrium constant.

This is the equation:

$K=Ae^{-Ea/RT}$

Where:

K is the equilibrium constant,
A is the frequency factor,
Ea is the activation energy (in J/mol),
T is the temperature in kelvins (K), and
R is the universal constant.

2) Substitute, using the right units, and compute:

A = 4.20 × 10¹² (dimensionless)
Ea = 67.0 kJ/mol = 67,000 J/mol
T = 24.0°C = 24.0 + 273.15 K = 297.15 K
R = 8.314 J/K mol

$K=Ae^{-Ea/RT}=(4.20)(10)^{12}e^{-67,000J/mol/(8.314J/molK.297.15K)}$

K = 7.00

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3 years ago

IF CORRECT I WILL GIVE BRAINLIEST

Vilka [71]

I think it’s B
Sorry if I’m wrong

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What is the molarity of the Ca(OH)2 solution if 32.00 mL of Ca(OH)2 requires 16.08 mL of a 2.303 M solution for complete titrati

amm1812

Answer:

For this problem we just need to remember the equation and that the volume is always in liters: MaVa=MbVb

Ma= 1.338 mol/L Va= 18.75 mL= 0.01875 L Mb= x Vb=24.73 mL= 0.02473 L

So now we can plug into the equation and solve:

1.338 mol/L * 0.01875 L= x mol/L * 0.02473 L

This is a two step process: stoichiometry and using the answer from the first part to plug and chug it into the Molariy equation.

First step: setup the stoichiometry problem:

3.1171 g Na2CO3 * (1 mol/106 g) * (2 mol HCl/ 1 mol Na2CO3)= mol HCl

Second step: Molarity equation

Molarity= moles HCl/ L M= mol HCl/0.04027 L

For the third problem, you will just use the same equation as the first: MaVa= MbVb

Ma=0.57 M Va= x L Mb= 0.875 M Vb= 23.83 mL= 0.02383 L

0.57 M * x L= 0.875 M * 0.02383 L

With this equation, we want to find the moles of NaOH by using the molarity equation first then because MaVa= MbVb, we know that the number of moles has to be equal.

0.75 M= x mol/ 0.0227 L mol NaOH = 0.75 M *0.0227 L mol NaOH= 0.017025

So next, we can set it to the mass of the acid using this equation: Molar Mass= mass/ moles

Molar Mass= 3.6 g/ 0.017025 mol

And with that you will find the molar mass of HX, and even determine what X is.

Explanation:

hope I helped

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True or false. The center of gravity and center of mass of an object need to be in the same spot?

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Answer:

True................

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