2 years ago

I need all solutions

Chemistry

1 answer:

marshall27 [118]2 years ago

6 0

Answer:

Answer is in the attachment

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2. (2 pts) How would you prepare 1.5 liters of 2 M KCI (MW=74.55 g/mol)

ra1l [238]

Answer:

Dissolve 226 g of KCl in enough water to make 1.5 L of solution

Explanation:

1. Calculate the moles of KCl needed

$n = \text{1.5 L} \times \dfrac{\text{2 mol}}{\text{1 L}}= \text{3.0 mol}$

2. Calculate the mass of KCl

$m = \text{3.0 mol} \times \dfrac{\text{74.55 g}}{\text{1 mol}}= \text{224 g}$

3. Prepare the solution

Measure out 224 g of KCl.
Dissolve the KCl in a few hundred millilitres of distilled water.
Add enough water to make 1.5 L of solution. Mix thoroughly to get a uniform solution.

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Find the molarity of the following solutions: 0.5 moles of sodium chloride is dissolved to make 0.05 liters of solution.

vredina [299]

M(molarity)=moles/volume
M=.5mol/.05L=10M

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