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3 years ago

The image shows particles of salt dissolved in water.

Chemistry

2 answers:

aalyn [17]3 years ago

6 0

Answer:

Salt particles will diffuse and towards where it is less that is left !!

so your answer is A !! left through diffusion !!

Explanation:

saw5 [17]3 years ago

3 0

Answer:

Salt particles will move toward the left through diffusion

Explanation:

I just took the quiz.

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How many milliliters of ammonium sulfate solution having a concentration of 0.218 M are needed to react completely with 62.6 ml

BartSMP [9]

Answer:

330 mL of (NH₄)₂SO₄ are needed

Explanation:

First of all, we determine the reaction:

(NH₄)₂SO₄ + 2NaOH → 2NH₃ + 2H₂O + Na₂SO₄

We determine the moles of base:

(First, we convert the volume from mL to L) → 62.6 mL . 1L/1000 mL = 0.0626L

Molarity . volume (L) = 2.31 mol/L . 0.0626 L = 0.144 moles

Ratio is 2:1. Therefore we make a rule of three:

2 moles of hydroxide react with 1 mol of sulfate

Then, 0.144 moles of NaOH must react with (0.144 .1) /2 = 0.072 moles

If we want to determine the volume → Moles / Molarity

0.072 mol / 0.218 mol/L = 0.330 L

We convert from L to mL → 0.330L . 1000 mL/1L = 330 mL

6 0

3 years ago

Cellular respiration uses glucose and oxygen, which have high levels of free energy, and releases carbon dioxide and water, whic

Alja [10]

Answer: Cellular respiration is spontaneous and exergonic. The energy released from the glucose is stored in ATP molelcules.

Explanation:

Spontaneous reactions have an increase in entropy (level of disorder) and a decrease in enthalpy (total energy). Cellular respiration goes from a more ordered state (one molecule of glucose) to a more disordered state (several molecules of CO2), and goes from a state with a lot of free energy to one with much less free energy. As a result, respiration is a spontaneous process.

As free energy from the glucose is released as ATP molecules during oxidation, the reaction is exergonic.

4 0

3 years ago

Read 2 more answers

Is this the correct answer?

Alona [7]

I believe so, looks like it

8 0

3 years ago

1) Given the balance equation below. Calculate how much Na3PO4 in grams you

juin [17]

Answer:

<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.

Explanation:

The balanced equation:

$Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}$

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

$\frac{164}{120}$

100 grams of NaOH is produced from =

$\frac{164}{120}\times100$ gram of Na3PO4

calculate,

= 136.67 g

8 0

2 years ago

If 100.0g of nitrogen is reacted with 100.0g of hydrogen, what is the excess reactant? What is the limiting reactant? Show your

Drupady [299]

N₂ : limiting reactant

H₂ : excess reactant

<h3>Further explanation</h3>

Given

mass of N₂ = 100 g

mass of H₂ = 100 g

Required

Limiting reactant

Excess reactant

Solution

Reaction

mol N₂(MW=28 g/mol) :

$\tt mol=\dfrac{mass}{MW}=\dfrac{100}{28}=3.571$

mol H₂(MW= 2 g/mol) :

$\tt mol=\dfrac{100}{2}=50$

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants

From the equation, mol ratio N₂ : H₂ = 1 : 3, so :

$\tt \dfrac{3.571}{1}\div \dfrac{50}{3}=3.571\div 16.6$

N₂ becomes a limiting reactant (smaller ratio) and H₂ is the excess reactant

5 0

2 years ago