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gladu [14]
3 years ago
12

What is the [h3o+] for a solution at 25°c that has poh = 5.640?

Chemistry
1 answer:
jonny [76]3 years ago
5 0

Answer:

= 4.37*10^-9 M

Explanation:

We know that;

pH + pOH = 14

Therefore;

pH = 14 - pOH

Which means; pH = 14 - 5.64

                               = 8.36

But;

pH = -log[H3O+]

Thus;

8.36 = -log[H3O+]

[H3O+] =  10^(-8.36)

        = 4.37*10^-9 M

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Consider the following reaction: NO( g) + SO 3( g) ⇌ NO 2( g) + SO 2( g) A reaction mixture initially contains 0.86 atm NO and 0
DIA [1.3K]

Answer:

The equilibrium pressure of NO2 is 0.084 atm

Explanation:

Step 1: Data given

A reaction mixture initially contains 0.86 atm NO and 0.86 atm SO3.

Kp = 0.0118

Step 2: The balanced equation

NO( g) + SO3( g) ⇌ NO2( g) + SO2( g)

Step 3: The initial pressures

p(NO) = 0.86 atm

p(SO3) = 0.86 atm

p(NO2) = 0 atm

p(SO2) = 0 atm

Step 4: The pressure at the equilibrium

For 1 mol NO we need 1 mol SO3 to produce 1 mol NO2 and 1 mol SO2

p(NO) = 0.86 -x atm

p(SO3) = 0.86 -xatm

p(NO2) = x atm

p(SO2) = x atm

Step 5: Define Kp

Kp = ((pNO2)*(pSO2)) / ((pNO)*(pSO3))

Kp = 0.0118 = x²/(0.86 - x)²

X = 0.08427

p(NO) = 0.86 -0.08427 = 0.77573 atm

p(SO3) = 0.86 -0.08427 = 0.77573 atm

p(NO2) = 0.08427 atm

p(SO2) = 0.08427 atm

The equilibrium pressure of NO2 is 0.08427 atm ≈ 0.084 atm

5 0
3 years ago
1.00176 x 103<br> Scientific notation
Ber [7]

Answer:

1.0318128 × 10^2

Explanation:

7 0
3 years ago
Determine the energy in joules of a photon whose frequency is 3.55 x10^17 hz( with units)
kogti [31]

i think it is this

Explanation:

3 0
3 years ago
An oil tanker spills a large amount of oil near the ocean shoreline. Which application of chemistry would best solve this proble
DochEvi [55]
I have heard they can use hair is stocking or nets to absorb the oil out of the water
3 0
3 years ago
Select the correct answer. Given: 2Al + 6HCl → 2AlCl3 + 3H2 If the chemical reaction produces 129 grams of AlCl3, how many grams
ivann1987 [24]

The reaction produces 2.93 g H₂.

M_r:                        133.34  2.016

        2Al + 6HCl → 2AlCl₃ + 3H₂

<em>Moles of AlCl₃</em> = 129 g AlCl₃ × (1 mol AlCl₃/133.34 g AlCl₃) = 0.9675 mol AlCl₃

<em>Moles of H₂</em> = 0.9675 mol AlCl₃ × (3 mol H₂/2 mol AlCl₃) = 1.451 mol H₂

<em>Mass of H₂</em> = 1.451 mol H₂ × (2.016 g H₂/1 mol H₂) = 2.93 g H₂

7 0
3 years ago
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