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Lubov Fominskaja [6]
3 years ago
11

Rosbel or Janette lol baakkaaa

Engineering
2 answers:
Svetllana [295]3 years ago
5 0

Answer:

t5g5gtttttttttttttttttttttttttttttttttttttttttttt

Explanation:gt555555555555555555555555555555555555555555555555

mezya [45]3 years ago
3 0

Answer:

dawbkjbjwwjhjfbfjewfaekfhawkjndwkja

Explanation: dum*as*

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A column has a 4.8 cm by 8.7 cm rectangular cross section and a height 4 mm . The column is fixed at both ends and has a lateral
Elden [556K]
I’m literally so sorry
3 0
3 years ago
Engine vacuum is being discussed. Technician A says that when the engine is operating under light loads, engine vacuum is low. T
sdas [7]

Neither of the two technicians (Technician A and Technician B) is correct.

<h3>What is an engine vacuum?</h3>

An engine vacuum can be defined as a type of engine which is designed and developed to derive its force from air pressure that's being pushed against one side of the piston of an automobile, while having a partial vacuum on the other side.

In this scenario, we can infer and logically conclude that neither of the two technicians (Technician A and Technician B) is correct because engine vacuum is high when the engine is operating under light loads and vice-versa.

Read more on engine vacuum here: brainly.com/question/14602340

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6 0
2 years ago
PLEASE HELP QUICK!!
ivolga24 [154]

R01= 14.1 Ω

R02=  0.03525Ω

<h3>Calculations and Parameters</h3>

Given:

K= E2/E1 = 120/2400

= 0.5

R1= 0.1 Ω, X1= 0.22Ω

R2= 0.035Ω, X2= 0.012Ω

The equivalence resistance as referred to both primary and secondary,

R01= R1 + R2

= R1 + R2/K2

= 0.1 + (0.035/9(0.05)^2)

= 14.1 Ω

R02= R2 + R1

=R2 + K^2.R1

= 0.035 + (0.05)^2 * 0.1

= 0.03525Ω

Read more about resistance here:

brainly.com/question/17563681

#SPJ1

5 0
2 years ago
Which statement about cathode ray tubes (CRTs) is true?
yuradex [85]

Answer:

CRTs consume less power than LCDs.

hope it helps (^^)

# Cary on learning

6 0
2 years ago
HELP PLEASE!!!!!!!!!!!
MAXImum [283]
C is your answers!!!!!$3&2)//
7 0
3 years ago
Read 2 more answers
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