D is the answer. Hope this helped
Answer:
Explained below
Explanation:
The isohyetal method is one used in estimating Rainfall whereby the mean precipitation across an area is gotten by drawing lines that have equal precipitation. This is done by the use of topographic and other data to yield reliable estimates.
Whereas, the arithmetic method is used to calculate true precipitation by the way of getting the arithmetic mean of all the points or arial measurements that will be considered in the analysis.
Answer:
the three part are mass, spring, damping
Explanation:
vibrating system consist of three elementary system namely
1) Mass - it is a rigid body due to which system experience vibration and kinetic energy due to vibration is directly proportional to velocity of the body.
2) Spring - the part that has elasticity and help to hold mass
3) Damping - this part considered to have zero mass and zero elasticity.
Answer:
![0.14\ lb/in^{3}](https://tex.z-dn.net/?f=0.14%5C%20lb%2Fin%5E%7B3%7D)
Explanation:
Density is defined as mass ler unit volume, expressed as
![\rho=\frac {m}{v}](https://tex.z-dn.net/?f=%5Crho%3D%5Cfrac%20%7Bm%7D%7Bv%7D)
Where m is mass,
is density and v is the volume. For a sphere, volume is given as
![v=\frac {4\pi r^{3}}{3}](https://tex.z-dn.net/?f=v%3D%5Cfrac%20%7B4%5Cpi%20r%5E%7B3%7D%7D%7B3%7D)
Replacing this into the formula of density then
![\rho=\frac {m}{\frac {4\pi r^{3}}{3}}](https://tex.z-dn.net/?f=%5Crho%3D%5Cfrac%20%7Bm%7D%7B%5Cfrac%20%7B4%5Cpi%20r%5E%7B3%7D%7D%7B3%7D%7D)
Given diameter of 2.24 in then the radius is 1.12 in. Substituting 0.82 lb for m then
![\rho=\frac {0.82}{\frac {4\pi 1.12^{3}}{3}}=0.13932044952427\approx 0.14 lb/in^{3}](https://tex.z-dn.net/?f=%5Crho%3D%5Cfrac%20%7B0.82%7D%7B%5Cfrac%20%7B4%5Cpi%201.12%5E%7B3%7D%7D%7B3%7D%7D%3D0.13932044952427%5Capprox%200.14%20lb%2Fin%5E%7B3%7D)
Answer:
The amplitude of the absorbed mass can be found
for ka:
![X_{a} =0.002m=\frac{F_{0} }{K_{a} } =\frac{250}{K_{a} } =125000N/m](https://tex.z-dn.net/?f=X_%7Ba%7D%20%3D0.002m%3D%5Cfrac%7BF_%7B0%7D%20%7D%7BK_%7Ba%7D%20%7D%20%3D%5Cfrac%7B250%7D%7BK_%7Ba%7D%20%7D%20%3D125000N%2Fm)
now
![w^2=\frac{K_{a} }{m_{a} } \\m_{a} =\frac{K_{a} }{w^2} =\frac{125000}{[6000*2\pi /60]^2} =0.317kg](https://tex.z-dn.net/?f=w%5E2%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bm_%7Ba%7D%20%7D%20%5C%5Cm_%7Ba%7D%20%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bw%5E2%7D%20%3D%5Cfrac%7B125000%7D%7B%5B6000%2A2%5Cpi%20%2F60%5D%5E2%7D%20%3D0.317kg)