Answer:
0.58 m
Explanation:
In order to find the vertical distance the load lifts, we first need to find the magnitude of the resistance force. So, Rd = Fd' where R = resistance force = ?, d = resistance distance = 3.5 m, F = effort force = 155 N and d' = effort distance = 1.5 m.
So R = Fd'/d = 155 N × 1.5 m/3.5 m = 232.5 Nm/3.5 m = 66.43 N
Now, the vertical work done by the effort = vertical work done by load
Fy = Ry' where y = vertical distance moved by effort = 0.25 m and y' = vertical distance moved by resistance force
So, Fy = Ry'
y' = Fy/R
= 155 N 0.25 m/66.43 N
= 38.75 Nm/66.43 N
= 0.58 m
So, the vertical distance the lighter object moves is y' = 0.58 m
The three formula for finding out the 3 types of the slope of curve Q with respect to L should be explained below.
<h3>Three formulas:</h3>
1. Slope intercept form where the formula is y = mx + b
Here
y = variable
m = slope of line
x = variable
b = y intercept
2. Point slope form where the formula is y - y1 = m(x - x1)
Here
y = variable
y1 = y coordinate at the first point on line
m = the slope
x = variable
x1 = x coordinate at the first point on line
3. Standard slope form where the formula is ax + by = c
Here
a = x coefficent
b & c = constant term
learn more about formula here: brainly.com/question/24454271
Answer:
B. The website's certificate still has the old bank's name
Explanation:
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Answer:
At steady state output will be 2
Explanation:
We have given transfer function 
Input is unit step so 
We know that
, here
, is output
So output 

Taking 12 common from denominator

Now using partial fraction



On comparing coefficient A=4 and B = -2
Putting the values of A and B in Y(S)

Now taking inverse la place

Steady state means t tends to infinite
So output at steady state = 
Answer:
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