All categories

3 years ago

What is photolytic decomposition reaction ???

Chemistry

2 answers:

Mademuasel [1]3 years ago

8 0

Answer:

Photolytic decomposition is chemical reaction where photons are broken down and interacts with target molecules.

Explanation:

HOPE IT'S HELP

PLEASE MARK AS BRAINLEST ANSWER

kumpel [21]3 years ago

5 0

Answer:

<h3>Hope it helps yah (. ❛ ᴗ ❛.)</h3>

You might be interested in

Find the mass of one mole of FeSO4. Show your addition and multiplication

myrzilka [38]

Answer:

151g/mol

Explanation:

1 Fe =55 1 S =32 4 O =64

7 0

4 years ago

i need help on this question.....................................................................................?

Serga [27]

I am pretty sure your answer is B

8 0

3 years ago

Read 2 more answers

In this experiment, you will use a natural indicator to indirectly determine the H+ concentration of some common household solut

valentinak56 [21]

Some of the scientific questions that may be answered through the experiment are:

(1) What are the physical changes that may occur in the solution or the indicator when added with acidic/basic solution?

(2) How much of the indicator is needed in order to bring about a significant physical change in the solution to identify its H+ concentration?

if wrong i sry :(

4 0

3 years ago

Read 2 more answers

Fluidity is maximum in a. Solid b. Liquid c. Gas d. Liquid and gas

Phantasy [73]

The answer is C gas

8 0

3 years ago

The normal boiling point of a liquid is 282 °C. At what temperature (in °C) would the vapor pressure be 0.350 atm? (∆Hvap = 28.5

victus00 [196]

Answer:

The temperature at which the vapor pressure would be 0.350 atm is 201.37°C

Explanation:

The relationship between variables in equilibrium between phases of one component system e.g liquid and vapor, solid and vapor , solid and liquid can be obtained from a thermodynamic relationship called Clapeyron equation.

Clausius- Clapeyron Equation can be put in a more convenient form applicable to vaporization and sublimation equilibria in which one of the two phases is gaseous.

The equation for Clausius- Clapeyron Equation can be expressed as:

$\mathtt{In \dfrac{P_2}{P_1}= \dfrac{\Delta \ H _{vap}}{R} \begin {pmatrix} \dfrac{T_2 -T_1}{T_2 \ T_1} \end {pmatrix} }$

where ;

$P_1$ is the vapor pressure at temperature 1

$P_ 2$ is the vapor pressure at temperature 2

∆Hvap = enthalpy of vaporization

R = universal gas constant

Given that:

$P_1$ = 1 atm

$P_ 2$ = 0.350 atm

∆Hvap = 28.5 kJ/mol = 28.5 × 10³ J/mol

$T_1$ = 282 °C = (282 + 273) K = 555 K

R = 8.314 J/mol/k

Substituting the above values into the Clausius - Clapeyron equation, we have:

$\mathtt{In \dfrac{P_2}{P_1}= \dfrac{\Delta \ H _{vap}}{R} \begin {pmatrix} \dfrac{T_2 -T_1}{T_2 \ T_1} \end {pmatrix} }$

$\mathtt{In \begin {pmatrix} \dfrac{0.350}{1} \end {pmatrix} } = \dfrac{28.5 \times 10^3 }{ 8.314 } \begin {pmatrix} \dfrac{T_2 - 555}{555T_2} \end {pmatrix} }$

$\mathtt{In \begin {pmatrix} \dfrac{0.350}{1} \end {pmatrix} } = \dfrac{28.5 \times 10^3 }{ 8.314 } \begin {pmatrix} \dfrac{1}{555}- \dfrac{1}{T_2} \end {pmatrix} }$

$- 1.0498= 3427.953 \begin {pmatrix} \dfrac{1}{555}- \dfrac{1}{T_2} \end {pmatrix} }$

$\dfrac{- 1.0498}{3427.953}= \begin {pmatrix} \dfrac{1}{555}- \dfrac{1}{T_2} \end {pmatrix} }$

$- 3.06246906 \times 10^{-4}= \begin {pmatrix} \dfrac{1}{555}- \dfrac{1}{T_2} \end {pmatrix} }$

$\dfrac{1}{T_2} = \begin {pmatrix} \dfrac{1}{555}+ (3.06246906 \times 10^{-4} ) \end {pmatrix} }$

$\dfrac{1}{T_2} = 0.002108048708$

$T_2 = \dfrac{1}{0.002108048708}$

$\mathbf{T_2 }$ = 474.37 K

To °C ; we have $\mathbf{T_2 }$ = (474.37 - 273)°C

$\mathbf{T_2 }$ = 201.37 °C

Thus, the temperature at which the vapor pressure would be 0.350 atm is 201.37 °C

3 0

3 years ago

What is photolytic decomposition reaction ???​

What is photolytic decomposition reaction ???