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a_sh-v [17]
2 years ago
6

Which of the following reactions results in a decrease in entropy? 2SO2 (g) + O2 (g) yields 2SO3 (g) 2NH3 (g) yields N2 (g) + 3H

2 (g) 2H2O2 (aq) yields 2H2O (l) + O2 (g) NaHCO3 (aq) + HCl (aq) yields NaCl (aq) + H2O (l) + CO2 (g)
Chemistry
2 answers:
Marrrta [24]2 years ago
3 0
2SO2 (g) + O2 (g) yields 2SO3 (g)
SashulF [63]2 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

Entropy is defined as the degree of randomness of a substance.

For example, gases have more entropy as compared to liquids because molecules a gas have more kinetic energy due to which they move rapidly.

Also, when more number of moles are formed a chemical reaction then it means entropy has increased. But when there are less number of moles formed then it means there is a decrease in entropy.

Thus, we can conclude that the reaction 2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g) results in a decrease in entropy as 3 moles is giving 2 moles.

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3 years ago
A sample of an unknown gas occupies 5.51 L at 1.31 atm. What pressure would thisgas exert in a 0.520 L container if the temperat
weeeeeb [17]

Answer:

P₂ = 13.9 atm (3 sig. figs.)

Explanation:

The pressure (P), Volume (V) relationship with Temperature (T) & mass (n) held constant is an inverse proportionality. That is Boyles Law ...

P ∝ 1/V => P = k/V => k = P·V

For two pressure-volume conditions, the proportionality constant (k) remains constant where k₁ = k₂ and P₁·V₁ = P₂·V₂ => P₂ = P₁·V₁/V₂

Given:

P₁ = 1.31 atm.

V₁ = 5.51 L

P₂ = ?

V₂ = 0.520 L

V₂ = (1.31 atm)(5.51L)/(0.520L) = 13.88096154 atm (calc. ans.) = 13.9 atm (3 sig. figs.)

5 0
2 years ago
What does the formula H2O mean
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3 0
2 years ago
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Is heat a from of kinetic or potential energy?
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Explanation:

3 0
3 years ago
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What volume of a 0.550 M solution of potassium hydroxide (KOH) can be made with 19.9 g of potassium hydroxide?
Natalija [7]

Answer:

0.645 L

Explanation:

To find the volume, you need to (1) convert grams to moles (using the molar mass) and then (2) calculate the volume (using the molarity ratio). The final answer should have 3 sig figs to match the sig figs of the given values.

(Step 1)

Molar Mass (KOH): 39.098 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (KOH): 56.104 g/mol

19.9 grams KOH              1 mole
--------------------------  x  -----------------------  =  0.355 moles KOH
                                     56.014 grams

(Step 2)

Molarity = moles / volume                            <----- Molarity ratio

0.550 M = 0.355 moles / volume                 <----- Insert values

(0.550 M) x volume = 0.355 moles              <----- Multiply both sides by volume

volume = 0.645 L                                          <----- Divide both sides by 0.550

6 0
1 year ago
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