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2 years ago

How does increasing the temperature of a liquid below the boiling point affect

1 answer:

4 0

When the particles of a substance (usually a liquid) is heated up, its particles absorb the energy provided thereby increasing their kinetic energy resulting to more movement of the individual particles.

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Can I have help with this. I'm really stuck. thanks. the question is above.

evablogger [386]

Answer:

The density of gallium would be greater than aluminium and boron.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

As we move down the group densities increases because larger increase in mass occur with increase ion volume and greater sizes of elements down the group.

The boron, aluminium and gallium present in group thirteen. Boron is present in period two aluminium is present in period three and gallium is present in period four. So, atomic number of gallium is greater than boron and aluminium and it is appear as we move down the group. that's why gallium has larger size and greater value of density then boron and aluminium.

The value of density of gallium is 5.904 g/cm³.

3 0

2 years ago

For the following reaction, 25.2 grams of sulfur dioxide are allowed to react with 5.36 grams of oxygen gas. sulfur dioxide (g)

Marizza181 [45]

Answer:

Maximum amount of sulfur trioxide that can be formed = 26.822 g

Explanation:

The balanced chemical equation for the reaction

2SO₂ + O₂ -----> 2SO₃

25.2 grams of sulfur dioxide are allowed to react with 5.36 grams of oxygen gas. What is the maximum amount of sulfur trioxide that can be formed?

It is the limiting reagent (the reactant in the stoichiometric lesser amount) that determines how much product is formed or how much of the other reactant is formed.

So, we convert the masses of reactants present into number of moles to get a clearer picture.

(Number of moles) = (mass)/(molar mass)

For sulfur dioxide,

Mass present = 25.2 g

Molar mass = 64.066 g/mol

(Number of moles present) = (25.2/64.066)

(Number of moles present) = 0.39 moles

For Oxygen gas,

Mass present = 5.36 g

Molar mass = 32.0 g/mol

(Number of moles present) = (5.36/32)

(Number of moles present) = 0.1675 moles

But from the stoichiometric balance,

2SO₂ + O₂ -----> 2SO₃

2 moles of Sulfur dioxide reacts with 1 mole of Oxygen gas

If Sulfur dioxide was the limiting reagent,

0.39 moles would react with (0.39×1/2) moles of Oxygen gas; 0.195 moles of Oxygen gas.

This is more than the total amount of Oxygen gas present at the start of the reaction, hence, Sulfur dioxide cannot be the limiting reagent.

Oxygen gas as limiting reagent,

1 mole of Oxygen gas reacts with 2 moles of Sulfur dioxide,

0.1675 moles of Oxygen gas would react with (0.1675×2/1) of Sulfur dioxide; 0.335 moles of Sulfur dioxide.

This indicates that oxygen is truly the limiting reagent and Sulfur dioxide is the reagent that is present in excess.

So, now, we calculate the amount of Sulfur trioxide that can be obtained from this reaction setup (assuming a 100% conversion and the maximum amount of Sulfur dioxide formed)

2SO₂ + O₂ -----> 2SO₃

1 mole of Oxygen gas gives 2 moles of Sulfur trioxide,

0.1675 moles of Oxygen gas will give (0.1675×2/1) moles of Sulfur trioxide; 0.335 moles of Sulfur trioxide.

We then convert this to mass.

(Mass) = (number of moles) × (molar mass)

Molar mass of SO₃ = 80.066 g/mol

(Mass of SO₃ produced) = 0.335 × 80.066

(Mass of SO₃ produced) = 26.822 g.

Maximum amount of sulfur trioxide that can be formed = 26.822 g

Hope this helps!!

5 0

3 years ago

Read 2 more answers

Calculate the final temperature of a sample of carbon dioxide of mass 16.0 g that is expanded reversibly and adiabatically from

Pie

For your first question, that equation only works if your situation is occurring at a constant temperature. Your original question is such a situation - everything occurs at 298.15 K. Therefore, you can use this value in the equation to calculate work. For your second question, Charles' Law describes how the volume of gas changes as you heat or cool it, PROVIDED PRESSURE AND MOLES OF GAS REMAIN CONSTANT THE WHOLE TIME. In your original question above, temperature stays constant while volume changes. However, what they don't tell you is that this necessarily requires a change in either pressure or moles of gas. Because the question works with the same sample the of gas the whole time (i.e. moles are constant), it is pressure that is changing (and this change will occur according to Boyle's Law, since temperature and moles are held constant). Hope that clarifies things!

4 0

2 years ago

What is the production of H2O2(aq) + 2H+(aq) + 2I–(aq)

Nata [24]

Answer: math is gay

Explanation:

6 0

2 years ago

Read 2 more answers

How many mg of metallic ions are in 1.0 mL of 0.10 M LINO3

Anton [14]

Answer:

0.6941 mg

Explanation:

First we calculate how many LiNO₃ moles there are, using the given concentration and volume:

1.0 mL * 0.10 M = 0.10 mmol LiNO₃

As 1 mol of LiNO₃ contains 1 mol of Li, in the problem solution there are 0.10 mmol of Li (the only metallic ion present).

Now we convert Li milimoles into miligrams, using its atomic mass:

0.10 mmol Li * 6.941 mg/mmol = 0.6941 mg

8 0

2 years ago