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ella [17]
2 years ago
15

the student performed a second trial and accidentally added more sodium hydroxide to the flask than was needed to reach the end

point but recorded the final volume. would this error increase, decrease or have no effect on the calculated acid concentration for the second trial?
Chemistry
1 answer:
Harrizon [31]2 years ago
4 0

A greater volume of acid will be needed to neutralize the sodium hydroxide thereby making the calculated concentration of acid for the second trial to decrease.

Titration is usually a way of determining the concentration of an unknown solution by accurately measuring the volume of a known solution that reacts completely with the unknown solution.

The point when reaction is completed is indicated by the end point of the reaction. If more base (sodium hydroxide) is added to the flask, then more volume of acid will be needed to neutralize it thereby making the calculated concentration of acid for the second trial to decrease.

Learn more: brainly.com/question/1527403

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There is water on the pan of the scale as you measure the mass of an object. If you were to ignore the water, what would be the
mihalych1998 [28]
Remember that density refers to the "mass per unit volume" of an object.

So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.

In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is

As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:

density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml

The effect on density would be that it would erroneously appear to be greater

Hope this helps!

Good luck
6 0
3 years ago
A white crystalline salt conducts electricity when it is melted and when it dissolves in water.
sergeinik [125]

Answer: Option (a) is the correct answer.

Explanation:

Ionic salts are defined as the salts which tend to contain ionic bonds as there occurs transfer of electrons between its combining atoms.

So, when an ionic salt melts or it is dissolved in water then it will dissociate into its respective ions and as electricity is the flow of electrons or ions. Hence, this salt is then able to conduct electricity.

As covalent compounds are insoluble in water so, they do no dissociate into ions. Hence, they do not conduct electricity.

Similarly, metallic and network solids do not dissociate into ions either when melted or dissolved in water. Therefore, they also do not conduct electricity.

Thus, we can conclude that when a white crystalline salt conducts electricity when it is melted and when it dissolves in water then this bond is of ionic type.

7 0
3 years ago
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vredina [299]
<span>Argon and chlorine are both gases at room temperature because they are non-metals.</span>
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amm1812

Answer:

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d

4 0
2 years ago
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Answer:

KCl is the answers for the question

Explanation:

please give me brainlest

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