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frosja888 [35]
4 years ago
5

The following charges on individual oil droplets were obtained during an experiment similar to Millikan's. Determine a charge fo

r the electron On C, coulombs), and explain your answer: -3.204><10 -19 C; -4.806x10-19 C; ~8.0le10-19 C; - 1.442x10-8 C.
Chemistry
1 answer:
RSB [31]4 years ago
4 0

Answer:

- 1.602 x 10⁻¹⁹coulombs

Explanation:

Charge on individual oil droplet would be multiple of charge on one electron . So we will find out the minimum common factor of given individual charges that is the LCM of all the charges given.

LCM of given charges like 3.204 , 4.806 ,8.01 and 14.42 . We have neglected the power of ten( 10⁻¹⁹)  because it is  already a common factor to all.

The LCM  is 1.602 . So charge on electron is 1.602 x 10⁻¹⁹.

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Answer:

M = 33.6M .

Explanation:

Hello there!

In this case, according to the definition of molarity which is computed by dividing the moles of solute by the liters of solution, it is possible to realize that the moles of the solute are 12.6 mol and the liters of solution are 375/1000= 0.375 L and therefore the molarity of the solution can be calculated as follows:

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