1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bingel [31]
3 years ago
7

***30 POINTS!!!!

Chemistry
1 answer:
satela [25.4K]3 years ago
6 0

Answer:

Approximately 241 kJ/mol reaction.

Explanation:

How many moles of the reaction took place?

The coefficient in front of both NaOH and HCl are both one. In other words, one mole of the reaction will require one mole of NaOH and one mole and HCl.

\rm0.025\; L \times 0.100\; mol\cdot L^{-1} = 0.0025\; mol of both NaOH and HCl are available. As a result, 0.0025 moles of the reaction would have taken place.

How much heat was produced?

Approximate volume of the solution:

\rm 25.0 + 25.0 = 50.0\; mL.

Approximate mass of the solution:

\rm 50.0\; mL\times 1\;g\cdot mL^{-1} = 50.0\; g.

Q = c\cdot m \cdot \Delta T = \rm 50.0\; g \times 4.812\; J \cdot g^{-1} \cdot K^{-1} \times (25.5 - 23.0)\; K = 601.5\; J

Enthalpy change per mole reaction:

\displaystyle \Delta H = \frac{Q}{n} = \rm \frac{601.5\; J}{0.025\; mol} \approx 241000\; J\cdot mol^{-1} = 241\; kJ \cdot mol^{-1}.

You might be interested in
What is the coefficient for hydrogen in the balanced equation for the reaction of solid molybdenum(iv) oxide with gaseous hydrog
anastassius [24]

The  coefficient  for hydrogen  in  the  balanced  equation   of solid  molybdenum(iV)  oxide  with gaseous  hydrogen  is  2


 Explanation

Coefficient   is defined  to  as  a number  in front   of a chemical formula in a  balanced chemical equation.

   The  reaction   of   molybdenum (iv) oxide  with  gaseous  hydrogen  is  as below,


MoO2  + 2 H2→  Mo  +2 H2O

From   balanced equation above  the coefficient   for  H2  is  2  since  the number in  front of  H2  is 2



3 0
3 years ago
Technetium-104 has a half life of 18.0 minutes. how much of a 165.0 g sample remains after 90.0 minutes?
11Alexandr11 [23.1K]

The mass of 165.0 g sample that remains after 90.0 minutes is 5.16 grams

calculation

lambda㏑2/18= 0.0385

m(t)= 165 x e( 0.0385 x90)  =5.16g

8 0
3 years ago
Read 2 more answers
Which is a cause of polarity in water molecules?
Svetradugi [14.3K]

Answer:

an uneven charge between the oxygen molecule and 2 hydrogen molecules

Explanation:

8 0
3 years ago
Read 2 more answers
New nuclei and neutrons result from:
svet-max [94.6K]
I think the correct answer from the choices listed above is option C. New nuclei and neutrons result from <span>the splitting of an atom's nucleus. It is called nuclear fission where atoms are being split into smaller parts. Hope this answers the question. Have a nice day.</span>
3 0
3 years ago
How many moles are in 56.0g of N2
ioda

Answer:

2 mol

Explanation:

v= m/M

M(N2) = 28g/mol

v(N2) = 56/28 = 2 mol

8 0
2 years ago
Other questions:
  • Plastic sheet is transparent or translucent?
    9·1 answer
  • What part of Dalton’s atomic theory was later proved to be incorrect?
    9·2 answers
  • If two fluorine atoms bonded with each other what kind of bond would be involved?
    5·2 answers
  • Name the particle discovered by James<br> Chadwick in 1932.
    14·1 answer
  • Hof metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the
    7·1 answer
  • What is the vapor pressure of a solution that contains 70.0 mL of ether and 30.0 mL of benzene?
    9·1 answer
  • I'm having trouble understanding what "the difference in energy between the products and reactants from the surroundings" means.
    14·1 answer
  • Heyyy, please help, I only need the sentences for the words please. Thank uuu :)
    8·2 answers
  • 31. A mixture with sand, pink sugar and water would be best separated using
    5·1 answer
  • These mixed messages be impossable
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!