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AVprozaik [17]
3 years ago
6

Can anyone help if u know it pls!!

Physics
2 answers:
ozzi3 years ago
7 0

Answer:

Use Pythagorean theorem

19) A² + B² = C²

5.2² + 9.2² = C²

C = √111.68

C = 10.567875...

C ≈ 10.6

21) A² + B² = C²

B² = C² - A²

B² = 7.2² - 5.3²

B = √23.75

B = 4.873397...

B ≈ 4.9

LuckyWell [14K]3 years ago
4 0

Answer:

(1)

H² = B² × L²

H² = (9.2)² × (5.2)²

H² = 84.64 × 27.04

H² = 2288.6656

H = √ 2288.6656

H = 47.84

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Consider a 40,000 km steel pipe in the shape of a ring that fits snuggly all around the circumference of the Earth. We are heati
Tatiana [17]

Answer:

The Height is  H = 70.02 m

Explanation:

We are given that the

                         Initial length is  = 40000\ Km = 40,000 *10^{3} m

from what we are told in the question the circumference of the circle is = 40,000 Km

  This means that the Radius would be :

         Let C denote the circumference

      So  

               C = 2 \pi r

      =>     r = \frac{C}{2 \pi}

               r = \frac{40,000}{2 \pi } = \frac{40,000*10^{3}}{2 *3.142}  = 6.365*10^6 m

We are told that 1-meter bar of steel that increases its temperature by 1 degree C will expand 11*10^{-6} meters

Hence

       The final length would be

                            40000*10^3 *(T + \alpha  )

Where T is the change in  temperature  \alpha is the Coefficient of linear expansion for steel

  let L_{final} denote the final length

   So

        L_{final} =40000*10^{6} *[1+ 11*10^{-6}]

                  = 40000440 \ m

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         Height(H) \ = \frac{change \ in \ radius \ }{2 \pi}

                       = \frac{(40000440-40000*10^3)}{2*3.142}

                       = 70.02m

3 0
4 years ago
Satellite A orbits a planet at a distance d from the planet’s center with a centripetal acceleration a0. A second identical sate
leva [86]

To solve this problem it is necessary to use the concepts related to the Gravitational Force and Newton's Second Law, as far as we know:

F_g = \frac{GMm}{r^2}

Where,

G = Gravitational constant

M = Mass of earth (in this case)

m = mass of satellite

r = radius

In the other hand we have the second's newton law:

F = ma

Where,

m = mass

a = acceleration

Equation both equations we have,

ma = \frac{GMm}{r^2}

For the problem we have that,

<em>Satellite A:</em>

ma_A = \frac{GMm}{r^2}

<em>Satellite B:</em>

ma_B = \frac{GMm}{(2r)^2}

The ratio between the two satellites would be,

\frac{ma_A}{ma_B}= \frac{\frac{GMm}{r^2}}{\frac{GMm}{(2r)^2}}

Solving for a_B,

a_B = \frac{a_A}{4}

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7 0
3 years ago
The apparent reversal of motion of planets against the backdrop of fixed stars is called
Free_Kalibri [48]

The planets move eastward against the background of fixed stars with the exception of Venus, Uranus and Pluto moving westward as seen in Earth's sky . This apparent retreating movement is called Retrograde motion. It is illusion created by Earth's movement going by outer planets in their respective orbits.

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3 years ago
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Which equation can be used to solve for acceleration?<br> t=v/a<br> vf=at-vi<br> a=d/t<br> v=a/t
postnew [5]

Answer:

t=v/a

Explanation:

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The change in velocity per unit of time is the acceleration

 From this equation;

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This expression is analogous to the expression chosen.

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3 years ago
What is the name of the small early planets, which formed through gravitational attraction reaching sizes of a few miles to even
Svetradugi [14.3K]

Answer:

Planetesimals  (Ex, Mercury, Venus , Mars & Earth)

Explanation:

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They are small early planets , which also has gravitational attraction.

Thanks

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