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Marta_Voda [28]
3 years ago
14

It takes 23 hours 56 minutes and 4 seconds for the earth to make one revolution (mean sidereal day). What is the angular speed o

f the earth
Physics
1 answer:
pychu [463]3 years ago
6 0

Answer:

The angular speed of the Earth is approximately 7.292\times 10^{-5} radians per second.

Explanation:

We suppose that Earth rotates at constant angular speed. From Rigid Body Physics, we remember that angular speed of the planet (\omega), measured in radians per second, is:

\omega = \frac{2\pi}{T} (Eq. 1)

Where T is the period, measured in seconds.

Therefore, the angular speed of the planet is:

\omega = \frac{2\pi}{23\,h\times \frac{3600\,s}{1\,h}+56\,min\times 60\,\frac{s}{min}+4\,s  }

\omega \approx 7.292\times 10^{-5}\,\frac{rad}{s}

The angular speed of the Earth is approximately 7.292\times 10^{-5} radians per second.

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Steven carefully places a 1.65-kg wooden block on a frictionless ramp, so that the block begins to slide down the ramp from rest
nadya68 [22]

Answer:

a. Gravity and c. Spring

Explanation:

Formula for work energy W = \vec{F} \bullet \vec{S} = FScos(\alpha)

whereas F is the force acting on the block, S is the distance traveled, and \alpha is the angle between 2 vectors F and S.

If F is perpendicular to S, then

\alpha = 90^o

cos(\alpha) = cos(90^o) = 0

W = FS*0 = 0

a. Normal force is the reaction force acting from the ramp back on the wooden block. This force is perpendicular to the direction of sliding. Therefore this force would do no work.

b. Gravity is the force acting downward, this would have an angle of 90^o - 58.3^o = 31.7^o degrees so the work is non-zero.

c. Spring force would have the same direction as sliding so the work is non-zero.

d. Friction force would have the same direction as sliding. However, as this is a frictionless ramp, the friction coefficient would be 0. Friction force would also be zero and so as its work.

5 0
4 years ago
The Milky Way galaxy (pictured above) is an example of a(n) __________________ galaxy. At the center of the galaxy is a galactic
OlgaM077 [116]
I think the answer is A.
8 0
3 years ago
Read 2 more answers
Wat's the definition of microwave spectroscopy
ivann1987 [24]

Answer:

Microwave spectroscopy is the spectroscopy method that employs microwaves, i.e. electromagnetic radiation at GHz frequencies, for the study of matter

6 0
4 years ago
Um carro viaja de uma cidade A a uma cidade B, distantes 200km.seu percurso demora 4 horas ,pois decorrida uma hora de viagem ,o
Aleksandr-060686 [28]

Answer: B

Explanation:

5 0
3 years ago
A car moving at 10 m/s crashes into a large bush and stops in 1.3 m. Using the Work-Energy theorem, calculate the average force
ad-work [718]

Answer:

The magnitude of the average force the seat belt exerts on the passenger is 2692.3 N.

It takes 0.26 s to bring the passenger in the car to a halt.

Explanation:

Hi there!

The negative work (W) needed to bring a moving object to stop is equal to its kinetic energy (KE):

W = KE

F · s = 1/2 · m · v²

Where:

F = applied force on the passenger.

s = displacement of the passenger.

m = mass of the passenger.

v = velocity of the passenger.

Solving the equation for F:

F = 1/2 · m · v² / s

Replacing with the data:

F = 1/2 · 70 kg · (10 m/s)² / 1.3 m

F = 2692.3 N

The magnitude of the average force the seat belt exerts on the passenger is 2692.3 N.

According to the second law of Newton:

F = m · a

Where "a" is the acceleration of the passenger.

We also know from kinematics that the velocity of an object can ve calculated as follows:

v = v0 + a · t

Where:

v = velocity of the passenger at time t.

v0 = initial velocity.

t = time.

a = acceleration.

When the passenger stops, its velocity is zero. So replacing a = F/m, let´s solve the equation for the time it takes the passenger to stop:

v = v0 + a · t

0 = 10 m/s + (-2692.3 N/ 70 kg) · t

-10 m/s / (-2692.3 N/ 70 kg)  = t

t =0.26 s

It takes 0.26 s to bring the passenger in the car to a halt.

5 0
3 years ago
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