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Ket [755]
2 years ago
12

A boat travels north at a rate of 25.0 kilometers per hour (km/hr) relative to the current of the river. The current of the rive

r moves south at a rate of 10.0 km/hr relative to the ground. What is the rate of motion of the boat relative to the ground?
Physics
1 answer:
USPshnik [31]2 years ago
4 0

Answer:yes

Explanation:yes

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How do you draw an ear
Neporo4naja [7]

Answer:

drawing of ear step by step

8 0
3 years ago
Which is an example of a solution?
vladimir1956 [14]

Answer:

C

Explanation:

plato

6 0
3 years ago
Find the frequency of a wave with the wavelength 3.5 m and the speed is 50 m/s. <br>​
Andru [333]

Answer:

8.57 Hz

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 3.5 m

Velocity (v) = 30 m/s

Frequency (f) =?

The velocity, wavelength and frequency of a wave are related according to the equation:

Velocity = wavelength × frequency

v = λ × f

With the above formula, we can simply obtain the frequency of the wave as follow:

Wavelength (λ) = 3.5 m

Velocity (v) = 30 m/s

Frequency (f) =?

v = λ × f

30 = 3.5 × f

Divide both side by 3.5

f = 30 / 3.5

f = 8.57 Hz

Thus, the frequency of the wave is 8.57 Hz

7 0
2 years ago
A 4kg object has a momentum of 12 kg*m/s, what is the objects velocity?
Bezzdna [24]
Momentum = mass x velocity
12 = 4 x v | ÷ both sides by 4
12 ÷ 4 =v
v= 3 m/s
8 0
2 years ago
A rock is launched at angle theta=53.2∘ above the horizontal from an altitude of ℎ=182 km with an initial speed ????0=1.61 km/s.
Mariulka [41]

Answer:

The rock's final speed at the required altitude will be 42.24 m/s.

Explanation:

Let's start by finding the initial vertical speed.

Vertical Speed = 1.61 * Sin (53.2°)

Vertical Speed = 0.8 m/s

We want to know the speed of the rock when it is at an altitude of 91 km.

The total displacement of the rock from its starting position will thus be equal to -91 km

We can use this in the following equation:

s=u*t+\frac{1}{2} (a*t^2)

-91=0.8*t+\frac{1}{2} (-9.8*t^2)

t = 4.3918 seconds

Thus it takes 4.3918 seconds to reach the required altitude. We can now find the speed as follows:

V=U+at

V=0.8+(-9.8)*(4.3918)

V = -42.24

Thus the rock's final speed at the required altitude will be 42.24 m/s.

8 0
3 years ago
Read 2 more answers
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