B. Universal Gravitational Law
Answer:
v_h = 9 m/s
Explanation:
given,
mass of the rocket = 1500 kg
accelerates = 10 m/s²
time = 4 s
one fragment is twice as massive as the other.
maximum height reached by the lighter fragment = 530 m
now,
using equation of motion to calculate the velocity
initial velocity of rocket,u = 0 m/s
v = u + a t
v = at.......(1)
total mass of the rocket
M = m + m'
m' is the heavier particle mass.
m' = 2 m (from the statement given in the question)
M = 3 m
m = M/3
now, again using equation of motion to calculate the initial velocity of the lighter particle.
v² = u² + 2 a s
0² = u² + 2 g h
u = √2gh.....(2)
now,
using conservation of momentum,





2 v_h = 18
v_h = 9 m/s
speed of the heavy fragment is equal to 9 m/s
The diameter of the sphere is 2cm.
<h3>How to calculate the diameter?</h3>
From the diagram, the first sphere on the ruler is at 4cn and the last sphere is at 12cm.
Therefore, the length will be:
= 12 - 4.
= 8cm
The diameter of one sphere will be:
= Length / 4
= 8/4
= 2
Therefore, the diameter of the sphere is 2cm.
Note that the second question wasn't found online.
Learn more about diameter on:
brainly.com/question/358744
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In order
Transverse
Gamma, Infrared, natural light, microwave, radio, and ultraviolet
1-trough, 2-crest, 3-length, 4-amplitude
In order A, C, D, C
directly
High pitched
Low/base pitched
I hope this helps!
Acceleration due to gravity is contract for the purposes of this question, so the acceleration would remain at 9.8 m/s^2