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patriot [66]
3 years ago
5

Rewrite the following integer 169 as a base and exponent without using an exponent of 1.

Mathematics
1 answer:
Westkost [7]3 years ago
5 0

Step-by-step explanation:

169 = (13)²

169 is the square of 13.

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Ac is tangent to circle o at point c what is the length of ac?
MissTica

Answer:

The Answer is 12

Step-by-step explanation:

Use Pythagorean theorem. AB=8 and BO=5 We still need to find AO

AO=AB+BO

8+5

AO=13

Now solve for AC

AC^2 + OC^2= AO^2

AC^2+5^2=13^2

AC^2+ 25=169

AC^2=144

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The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

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⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

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