According to the question, the object is placed at 2F
The ray diagram is shown in the figure attached.
According to the figure:
Object AB is at 2F₁
First, we draw a ray parallel to principal axis.
So, it passes through focus after refraction.
We draw another ray which passes through optical center.
So, the ray will go through without any deviation.
Where both refracted rays meet is point A' and the image formed is A'B'
This image is formed at 2F₂
We can say that:
- Image is real.
- Image is inverted.
- Image is exactly the same size as the object.
Answer:
[H3O+] = 0.00520 M
Explanation:
The dissociation of acetic acid in water is given by the equation;
CH3COOH + H2O<-------> H3O+ + CH3COO-
ka = [H+][C2H3O2-]/[HC2H3O2]
Ka = 1.8 x 10^-5
= x^2 / 0.150-x
x = [H3O+]= 0.00520 M
Answer:
As the skydiver falls to the Earth, she experiences positive acceleration only due to gravity.
Explanation:
As the skydiver falls to the Earth, she experiences friction in the form of air resistance which tries to slow her down and is proportional to the her velocity. So it cannot have a positive acceleration as it acts in opposite direction to slow her down.
Inertia during skydiving is experienced when we open an parachute, the parachute slows down the speed of are descent hence changing our inertia of motion with a velocity.
Only the Earth's, gravitational field has an positive acceleration as it pulls us towards the Earth, hence increasing our velocity.
Answer:
C. a ball at the top of a mountain
Explanation:
It has more potential energy because it is the highest from the ground. The higher it is, the more potential energy it has.
Answer:
Answer
Explanation:
It is given that,
The horizontal speed of a dart player =
12.4 m/s
The dart hits the board 0.32 m below the
height from which it was thrown.
We need to find how long it take the dart
to hit the board.
Let the time taken by the dart to hit the
board. Using second equation of motion
to find it.
1
y = ut +
2
=
at2
Put u = 0 and a=-g
-
-1
y =
1942
1
-0.32
=
x 9.8t2
2
2 x 0.32-0.32
=
t=
9.8
t= 0.255 s
Let x be the horizontal distance travelled.
It is calculated as follows:
X =
12.4 x 0.255
=
= 3.16 m
So, the dart will hit the board at a
distance of 3.16 m.
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