Answer: The noble gas preceding tin is Krypton [Kr].
Explanation: Atomic Number of tin is 50 , Atomic Number of neon is 10, Atomic Number of argon is 18, Atomic Number of krypton is 36 and Atomic Number of xenon is 54.
Atomic number tells us the number of electrons present in the atom.
Thus the electronic configuration of tin according to increasing energy of orbitals is written as ![[Kr]4d^105s^25p^2](https://tex.z-dn.net/?f=%5BKr%5D4d%5E105s%5E25p%5E2)
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The question is incomplete. The complete question is :
C. Balance these fossil-fuel combustion reactions. (1 point)
C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat
CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
Solution :
C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat
When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.
CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat
When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.
C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat
When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.
C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat
When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.
Answer:
The volume when the conditions were altered is 0.5109 L or 510.9 mL
Explanation:
Using the general gas equation,
P1 V1 / T1 = P2 V2 / T2
where;
P1 = 756 mmHg
V1 = 475 ml = 0.475 L
T1 = 23.5°C = 23.5 + 273K = 275.5 K
P2 = 722 mm Hg
T2 = 10°C = 10 + 273 K = 283 K
V2 = ?
Rearranging to make V2 the subject of the formula, we obtain:
V2 = P1 V1 T2 / P2 T1
V2 = 756 * 0.475 * 283 / 722 * 275.5
V2 = 101, 625.3 / 198911
V2 = 0.5109 L or 510.9 mL
Explanation:
Homogeneous catalysis refers to catalytic reactions where the catalyst is in the same phase as the reactants.
Heterogeneous catalysis is the type of catalysis where the phase of the catalyst differs from the phase of the reactants or products.
Platinum is used to catalyze the hydrogenation of ethylene:
H2(g)+CH2CH2(g)− ⟶ Pt(s) CH3CH3(g)
In this reaction, the platinum is in the solid state. While the other species (reactants and products) are in their gaseous state.
This reaction is Heterogenous catalysis.
Chlorofluorocarbons (CFCs) catalyze the conversion of ozone (O3O3) to oxygen gas (O2O2):
2O3(g)− ⟶ CFC(g) 3O2(g)
The catalyst is in the same gaseous state as the reactant and product.
This reaction is Homogenous catalysis.
Magnesium catalyzes the disproportionation of hydrogen peroxide to produce water and oxygen:
2H2O2(aq)− ⟶ Mg(s) 2H2O(l) + O2(g)
In this reaction, the Magnesium is in the solid state. While the other species (reactants and products) are in their gaseous state.
This reaction is Heterogenous catalysis.
Answer: As for vapor pressure being higher at higher temperatures, when the temperature of a liquid is raised, the added energy in the liquid gives the molecules more energy and they have greater ability to escape the liquid phase and go into the gaseous phase.
Explanation:
