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patriot [66]
3 years ago
8

Scott received scores of 91, 85, and 89 on three tests. What score must Scott get on the fourth test to have an overall average

score of 90?
either :
a:88
b:89
c:90
d:95
Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0
The answer is 95 cause it is the most. 
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Eighty percent of a number.?as a alegrabatic expression.
Andrews [41]

Answer:

\frac{4}{5} x

or

0.8x

Step-by-step explanation:

80\% \: of \: x =  \frac{80}{100}x \\  \frac{80}{100}  x =  \frac{8}{10}x =  \frac{4}{5}  x = 0.8x

6 0
3 years ago
Suppose that you flip a coin 13 times. What is the probability that you achieve at least 5 tails?
wariber [46]
Heads, or tails. It's 1/2 a chance, because either way you will either land heads or tails. It would be a probability of 1-(1/2)^5. Can you solve that?
5 0
3 years ago
Chocolate chip cookies have a distribution that is approximately normal with a mean of 24.2 chocolate chips per cookie and a sta
Allisa [31]

Answer:

Percentile 5

z=-1.64

And if we solve for a we got

a=24.2 -1.64*2.6=19.94

Percentile 95

z=1.64

And if we solve for a we got

a=24.2 +1.64*2.6=28.46

Step-by-step explanation:

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(24.2,2.6)  

Where \mu=24.2 and \sigma=2.6

We want to find the percentiles 5 and 95 for this case.

Percentile 5

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.95   (a)

P(X   (b)

We want to find a percentile with 0.95 of the area on the left and 0.05 of the area on the right it's z=-1.64. On this case P(Z<-1.64)=0.05 and P(z>-1.64)=0.05

Using this condition we got:

P(X  

P(z

Replacing we got:

z=-1.64

And if we solve for a we got

a=24.2 -1.64*2.6=19.94

Percentile 95

z=1.64

And if we solve for a we got

a=24.2 +1.64*2.6=28.46

4 0
3 years ago
Need help with angles need it today
givi [52]
ANSWER: adjacent angles
3 0
3 years ago
Can you factor x^2+6z+12 please
Gemiola [76]
To solve we have to write 12x as 2x+10x 
<span><span>x2</span>+2x+10x+20</span>
taking x and 10 as a common
x(x+2)+10(x+2)
now (x+2) is common
<span>(x+2)(x+10) answer</span>
6 0
3 years ago
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