I believe this is a copy of an angle
The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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Answer:
y = 8 or y = 0
Step-by-step explanation:
Solve for y over the real numbers:
y^2 - 8 y = 0
Factor y from the left hand side:
y (y - 8) = 0
Split into two equations:
y - 8 = 0 or y = 0
Add 8 to both sides:
Answer: y = 8 or y = 0
Answer: C. Definition of an Altitude
Step-by-step explanation:
Given: In triangle MNO shown below, segment NP is an altitude from the right angle.
Let ∠MNP=x
Then ∠PNO=90°-x
Therefore in triangle MNO,
∠MPN=∠NPO =90° [by definition of Altitude]
[Definition of altitude : A line which passes through a vertex of a triangle, and joins the opposite side forming right angles. ]
Now using angle sum property in ΔMNP
∠MNP+∠MPN+∠PMN=180°
⇒x+90°+∠PMN=180°
⇒∠PMN=180°-90°-x
⇒∠PMN=90°-x
Now, in ΔMNO and ΔPNO
∠PMN=∠PNO=90°-x
and ∠MPN=∠NPO =90° [by definition of altitude]
Therefore by AA similarity postulate, we have
ΔMNO ≈ ΔPNO
