The question is incomplete, the complete question is;
Why is a terminal alkyne favored when sodium amide (NaNH2) is used in an elimination reaction with 2,3-dichlorohexane? product. A) The terminal alkyne is more stable than the internal alkyne and is naturally the favored B) The terminal alkyne is not favored in this reaction. C) The resonance favors the formation of the terminal rather than internal alkyne. D) The strong base deprotonates the terminal alkyne and removes it from the equilibrium.
E) The positions of the Cl atoms induce the net formation of the terminal alkyne.
Answer:
E) The positions of the Cl atoms induce the net formation of the terminal alkyne.
Explanation:
In this reaction, sterric hindrance plays a very important role. We know that sodamide is a strong base, it tends to attack at the most accessible position.
The first deprotonation yields an alkene. The strong base attacks at the terminal position again and yields the terminal alkyne. Thus the structure of the dihalide makes the terminal hydrogen atoms most accessible to the base. Hence the answer.
Answer:
0.30M HOAc
Explanation:
Given 250.0ml (0.96M HOAc) => 800ml(??M HOAc)
Use the dilution equation...
(Molarity x Volume)concentrated soln = (Molarity x Volume)dilute soln
(0.96M)(250.0ml) = (Molarity diluted soln)(800ml)
Molarity diluted soln = (0.96M)(250.0ml)/(800ml) = 0.30M HOAc
Answer:
[OH⁻] = 8x10⁻¹⁰
Explanation:
Kw = 1x10⁻¹⁴
Kw = [H₃O⁺] . [OH⁻]
1x10⁻¹⁴ = 1.25x10⁻⁵ . [OH⁻]
1x10⁻¹⁴ / 1.25x10⁻⁵ = [OH⁻]
[OH⁻] = 8x10⁻¹⁰
Answer:
Explanation:
An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.
All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.
Isotopic notation: Protons Neutrons Electrons
¹⁹⁷₇₉Au 79 118 79
Solution:
p+n = atomic mass = 79+118 = 197
e = 79 (atomic number) so the element with atomic number Au.
Isotopic notation: Protons Neutrons Electrons
⁷⁹₃₅Br 35 44 35
Solution:
Number of neutrons = atomic mass - number of protons= 79-35 = 44
Number of protons and electrons are equal so number of electrons are 35.
Isotopic notation: Protons Neutrons Electrons
¹²⁷₅₃I 53 74 53
Solution:
The atomic number of iodine is 53.
Number of neutrons = atomic mass - number of protons= 127-53 = 74
Number of protons and electrons are equal so number of electrons are 53.
Isotopic notation: Protons Neutrons Electrons
⁵⁶₂₆Fe 26 30 26
Solution:
The atomic number of iron is 26.
atomic mass = n+p= 26+30= 56
Number of protons and electrons are equal so number of electrons are 26.
