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jek_recluse [69]
3 years ago
8

2. If AD= 2x – 1 and BC = 5x – 13, then AD= BC= AB= DC =

Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0

Answer:

the question is missing a relation between AD AND BC

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Need help due in 10 mins
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A) The amount of money deposited monthly

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2 years ago
Need help please, does any one know how to do this​
ziro4ka [17]

Answer:

  • (6-u)/(2+u)
  • 8/(u+2) -1
  • -u/(u+2) +6/(u+2)

Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

  (-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

  (6 -u)/(u +2)

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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

  -(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

or

  8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

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3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

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4) You can also multiply numerator and denominator by some constant, say 3:

  -(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

  (1+x^2)(6 -u)/((1+x^2)(u+2))

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3 years ago
If m<3 = 54° find each measure.
oee [108]

Answer:

m<15

Step-by-step explanation:

m<15 promise ko heheh

8 0
2 years ago
Find the distance between points (5,1) and (3,4) to the nearest tenth
Charra [1.4K]

Answer:

3.6 units (nearest tenth)

Step-by-step explanation:

distance formula

= \sqrt{(x1 - x2)^{2}  + (y1 - y2)^{2} }

Thus, distance between the 2 points

= √[(5 - 3)² + (1 - 4)²]

= √[ 2²+ ( - 3)²]

= √13

= 3.6 units (nearest tenth)

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3 years ago
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