The price would not be a physical property
Answer:
C. Rate = k[H2]^2[O2]
Explanation:
Rate law only cares about REACTANTS. Since, rate law can only be determined experimentally, I am assuming the given reaction mechanism is elementary reaction from which we can write the rate law.
Only H2 and O2 are part of rate law since they are reactants and also the coefficient in front of H2 goes as exponent on rate law to indicate the order of H2 in the reaction.
Rate= k [H2]^2 [O2]
Answer:
Use the equation E = hf
Explanation:
A good site to use to figure this out I used it too is https://study.com/academy/lesson/energy-momentum-of-a-photon-equation-calculations.html
Good luck!
Answer:
1. ClF₅ ; 2. TeF₆ ; 3. S₂F₁₀ ; 4. P₄O₁₀ ; 5. Br₂O ; 6. H₂S₂ ; 7. SO ; 8. NO₃ ;
9. S₂O ; 10. C₃N₄
Explanation:
Let's count the atoms, by the name
1. Chlorine Pentaflouride
1 Cl and 5F → ClF₅
2. Tellurium Hexafluoride
1 Te and 6F → TeF₆
3. Disulfur decafluoride
2 S and 10 F → S₂F₁₀
4. Tetraphophorus Decaoxide
4 P and 10 O → P₄O₁₀
5. Dibromine Monoxide
2 Br and 1 O → Br₂O
6. Dihydrogen Disulfide
2 H and 2 S → H₂S₂
7. Sulfur monoxide
1 S and 1 O → SO
8. nitrogen trioxide
1 N and 3 O → NO₃
9. oxygen monosulfide
1 O and 1 S₂ → S₂O
10. tricarbon tetranitride
3 C and 4 N → C₃N₄
