Write a mechanism for the esterification of propanoic acid with 18O-labeled ethanol. Show clearly the fate of the 18O label. (b)
1 answer:
Answer:
See explanation and images attached
Explanation:
a) In the mechanism for the acid catalysed esterification of propanoic acid using ethanol, we can see that the first step is the protonation of the acid followed by nucleophillic attack of the alcohol. Loss of water and consequent deprotonation regenerates the acid catalyst. We can see the fate of the 18O labelled ethanol in the mechanism shown.
b) In the second mechanism, an unnamed ester is hydrolysed using an acid catalyst. The attack of the acid and subsequent nucleophillic attack of water labelled with 18O leads to the incorporation of this 18O into the product acid as shown in the mechanism attached to this answer.
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Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Answer:
See explanation and image attached
Explanation:
The IUPAC system of nomenclature enables the structure of molecules to be written seamlessly from the name of the compound. Hence it is commonly called the systematic nomenclature.
The parent chain here is propane. It is substituted at the 2- position by a methyl group and at the 3-position by 4-chlorophenyl group as we can see in the image attached to this answer.
