Answer:
0.92moles
Explanation:
Given reaction:
2Fe + 3Cl₂ → 2FeCl₃
Mass of FeCl₃ = 100g
Unknown:
Number of moles of Cl₂ needed = ?
Solution:
To solve this problem, we work from the known specie to the unknown.
From the mass of the FeCl₃ given, we can solve for the number of moles of the unknown.
- Number of moles of FeCl₃;
Number of moles = 
Molar mass of FeCl₃ = 56 + 3(35.5) = 162.5g/mol
Number of moles = 
= 0.62mole
From the reaction expression;
2 mole of FeCl₃ is produced from 3 moles of Cl₂
0.62 mole of FeCl₃ will be produced from 
= 0.92mole
The number of moles of Cl₂ = 0.92moles
Answer:
Answer is letter B
Explanation:
The first one is wrong because acids release H+, not bases.
The third one is wrong because the pH is exactly 7, not greater.
The last one is wrong because it is vague and does not fit a neutralization reaction.
Answer:
Planetary orbits are all nearly circular , comet orbits are highly excentric . ... This means that planets stay more or less at the same distance from the sun, while comets travel as far out as beyond Neptune, and can travel as far in as Mercury.
Answer:
The density of Ammonia : 6.25.10⁻⁴ g/cm³
Further explanation
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller density
The unit of density can be expressed in g/cm³ or kg/m³
Density formula:
\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}ρ = Vm
ρ = density
m = mass
v = volume
A common example is the water density of 1 gr/cm³
Ammonia has a density of 0.625 g/L, then convert to g/cm³ :
\begin{gathered}\rm 1~L=1~dm^3=10^3~cm^3\\\\0.625~\dfrac{g}{L}\times \dfrac{1~L}{10^3~cm^3}\\\\\rho=\dfrac{0.625}{10^3}}\dfrac{g}{cm^3}=\boxed{6.25.10^{-4}\dfrac{g}{cm^3}}\end{gathered}
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