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kap26 [50]
3 years ago
8

7. How many chlorine atoms are in a 34.2 g sample of dichlorine pentoxide?

Chemistry
1 answer:
Reptile [31]3 years ago
4 0

Answer:

The answer to your question is 1.36 x 10²³ atoms

Explanation:

Data

number of atoms = ?

mass of the sample = 34.2 g

Molecule = Cl₂O₅

Process

1.- Calculate the molar mass of Cl₂O₅

Cl₂O₅ = (35.5 x 2) + (16 x 5) = 71 + 80 = 151 g

2.- Calculate the atoms of Cl₂O₅

                     151 g of Cl₂O₅ ---------------- 6 .023 x 10²³ atoms

                       34.2 g of Cl₂O₅ ------------ x

                          x = (34.2 x 6.023 x 10²³) / 151

                          x = 1.36 x 10²³ atoms

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S + 6 HNO3 H2SO4 + 6 NO2 + 2 H2O
exis [7]

Answer:

              101.50 g H₂O

Explanation:

The mole ratio of HNO₃ and H₂O is 6 : 2

Hence, 16.9 moles of HNO₃ will produce = 2/6×16.9 = 5.63 moles of H₂O

Also,

Mass = Moles × M.Mass

Mass = 5.63 mol × 18.02 g/mol

Mass = 101.50 g H₂O

5 0
2 years ago
How many moles of ba(oh)2 are present in 275 ml of 0.200 m ba(oh)2?
DENIUS [597]
You have to put your attention to the unit of concentration. It is expressed in terms of molarity, which is represented in M. It is the number of moles solute per liter solution. So, you simply have to multiply the molarity with the volume in liters.

Volume = 275 mL * 1 L/1000 mL = 0.275 L
<em>Moles Ba(OH)₂ = (0.200 M)(0.275 L) = 0.055 mol</em>
6 0
3 years ago
Write an equation for the hydrogenation of glyceryl trilinolenate, a fat formed from glycerol and three linolenic acid molecules
Tomtit [17]

Balanced chemical equation for the hydrogenation of glyceryl trilinolenate:

C₅₇H₉₂O₆ + 9H₂ → C₅₇H₁₁₀O₆.

Linolenic acid (octadecatrienoic acids ) is a type of fatty acid. It has 18 carbon atoms chain and three double bonds. So trilinolenate has nine double bonds.

Trilinolenate is the form of triglyceride esters of linolenic acid.

Hydrogenation is addition of hydrogen atoms at both sides of a double bond.

5 0
3 years ago
To what temperature in kelvin will a 2.3 L balloon have to be heated to expand to a volume of 400 L Assume the initial temperatu
olchik [2.2K]

Answer:

T₂ = 51826.1 K

Explanation:

Given data:

Initial Volume = 2.3 L

Final volume = 400 L

Initial temperature = 25 °C (25+ 273 = 298 K)

Final temperature = ?

Solution:

V₁/T₁ = V₂/T₂

T₂ = V₂ T₁/V₁

T₂ =  400 L . 298 K / 2.3 L

T₂ = 119200 K. L / 2.3 L

T₂ = 51826.1 K

7 0
3 years ago
What is the density of a liquid if 12.5 ml of the liquid has a density of 9.80 g?
blagie [28]

Answer:

The answer is

<h2>0.784 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>density =  \frac{mass}{volume}</h3>

From the question

mass of liquid = 9.8 g

volume = 12.5 mL

The density is

density =  \frac{9.8}{12.5}

We have the final answer as

<h3>0.784 g/mL</h3>

Hope this helps you

3 0
3 years ago
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