Anaerobic transformations of 1,1,1-trichloroethane (TCA), 1,1-dichloroethane (DCA), and chloroethane (CA) were studied with sludge from a lab-scale, municipal wastewater sludge digester. TCA was biologically transformed to DCA and CA and further to ethane by reductive dechlorination. TCA was also converted to acetic acid and 1,1-dichloroethene (11DCE) by cell-free extract. 11DCE was further biologically converted to ethene. This pathway was confirmed by transformation tests of TCA, DCA and CA, by tests with cell-free extract, and by chloride release during TCA degradation.
Answer:
sublimation
Explanation:
solid => liquid Melting
liquid => solid freezing
liquid => gas evaporation
gas => liquid condensation
solid => gas sublimation
gas => solid deposition (e.g.; formation of frost), however some scholars will also refer to this process as sublimation.
Answer:
b. 16 protons, 18 neutrons, and 18 electrons
Explanation:
Things to be remembered
Negative charge on any ionic species indicates gained the electrons
Positive charge on any ionic species indicates lost the electrons
A sulfur atom has 16 protons, 18 neutrons, and 16 electrons, A sulfide ion has a 2– charge which indicates that sulphur has gained two electron from any other atom, ion or species!
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Answer:
mass of CO2 = 88 g
Explanation:
It is stated in question that 18.7 g of oxygen remained unreacted which means that carbon is limiting reactant. Thus the amount of carbon dioxide produced depend upon the amount of carbon.
Given data:
mass of carbon = 24 g
total mass of oxygen 82.7 g
mass of unreacted oxygen = 18.7 g
mass of carbon dioxide = ?
Solution:
First of we will calculate the moles of carbon.
number of moles of carbon = mass of carbon / atomic weight
number of moles of carbon = 24 g/ 12 g/mol = 2 mol
Chemical equation:
C + O2 → CO2
now we compare the number of moles of carbon and carbon dioxide,
C : CO2
1 : 1
2 : 2
Now we will calculate the mass of carbon dioxide from moles.
number of moles of CO2 = mass of CO2 / molar mass of CO2
2 mol × 44 g/mol = mass
mass of CO2 = 88 g
Urea is diffused more slowly because it’s larger than sodium.
